如何查找在线用户

Question

I was making a chat for my website. For that I need to find how many registered users are online. I count the number of sessions and store them in a table. When they logout, their name is removed from that table. Now if they don't click logout and directly close their tab, it does not make them go offline. Their name still exists in table. So to remove them, I found a very complicated algorithm online. It empties that table in every five minutes and then again add the names of the people who are online. But the problem is that while this happens, the chat is interrupted. So I need a way out for this problem

Answer 1

Add a column for "last active." Every time the user performs some action (which may include the browser polling for more messages via AJAX, for example) you update that column to NOW() . Then your query for finding active users can be something like:

SELECT user.name FROM user
    WHERE DATE_ADD(user.last_active, INTERVAL 5 MINUTE) >= NOW();

Deleting old records from the table is fine, but is probably an optional enhancement (depending on site load).

Answer 2

Maybe look into this: destroy session on window close?

Instead of destroying the session you could execute a query that deletes the row.

Answer 3

I think there are 2 solution.

1.) Save a timestamp and make a cronjob. The cron check every minute or 2 minuten how old the entries are and delete entries older then 5 minutes for example.

2.) Second way make a funktion which do the same as Point 1 but run the function on every page call. But this is not really efficiant and make a lot of load.

Answer 4

如果您将会话存储在db表中，则可以轻松检查活动的会话，请查看php手册http://in.php.net/manual/en/function.session-set-save-handler.php