onchange不工作jquery.selectbox

Question

In onchange event is not working in jquery.selectbox-05, i am using two dropdown box one for country another one state if i select the country the state will pickup automatically it's work in normal php dropdown but i use this code in jquery.selectbox it's not working anybody will help me

Here my code

<script type="text/javascript" src="scripts/jquery.selectbox-0.5.js"></script>
<script type= "text/javascript" src = "scripts/countries2.js"></script>
$(document).ready(function(){
    $('.selectBoxMedium').selectboxMedium();
    $('.selectBoxSmall').selectboxSmall();
    $('.selectBoxSmallest').selectboxSmallest();
    $('.selectBox').selectbox();
    $(document).pngFix(); 
});
<p class="formInput formSelectBox">
    <select onchange="print_state1('state',this.selectedIndex);" id="country" class= "selectBox data" name ="country"></select>
</p>

<p class="formInput formSelectBox">
    <select name ="state" id ="state" class="selectBox"></select>
    <script language="javascript">print_country1("country");</script>
</p>

Javascript functions:

function print_country1(country_id) {
    // given the id of the <select> tag as function argument, it inserts <option> tags
    var option_str = document.getElementById(country_id);
    var x, i=0;
    for(x in country_arr){
        option_str.options[i++] = new Option(country_arr[x],country_arr[x]);
    }
}

function print_state1(state_id, state_index) {
    var option_str = document.getElementById(state_id);
    var x, i=0;
    state_index++;
    var state_arr = s_a[state_index].split("|");
    for(x in state_arr) {
        option_str.options[i++] = new Option(state_arr[x],state_arr[x]);
    }
}

Answer 1

Here's your problem... this plugin don't handle with dynamic options. I mean, when you do $element.selectbox() the plugin executes with the actual options for the select element and will not update the selectbox if you changes the options.

So, if you have a select element with no options and run the selectbox plugin, it will create a selectbox with no options elements. When you changes the country and do a "reload" in the options for select#states , all the states for the selected country are loaded and added as options for select#states element, but the plugin selectbox was executed in page load and will not reload the options in their elements :(

How to fix it? In your case, you should be able to remove the siblings of select#state (generated by selectbox plugin), update the options with new state values and then run again the selectbox plugin :)

Check this functional jsfiddle :)

PS: this fiddle is working with countries-3.1.js , the jquery.selectbox-0.5 and no CSS

Answer 2

The problem with this plugin is it cannot handle the onchange() event because of that we are mostly irritate. So, here is the solution for that..

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js" type="text/javascript" charset="utf-8"></script>
<script src="jquery.selectbox-0.5.js" type="text/javascript" charset="utf-8"></script>

<script type="text/javascript">
$(document).ready(function() {
    $('.items').selectbox();
                $('#country_input').blur(function(){
                   setTimeout(function(){
                       var e = document.getElementById("country");
                       var countryCode = e.options[e.selectedIndex].value;
                       getState('state',countryCode);
                   },500)                        

                });
});

</script>

<script type="text/javascript">
function getState(state_id, countryCode)
{
var option_str = document.getElementById(state_id);
option_str.length=0;
option_str.options[0] = new Option('Select State','');
option_str.selectedIndex = 0;
//write your code to get state list with the use of "countryCode"
var state_arr = stateListArray; //assume "stateListArray" is an array which is holding list of states
for (var i=0; i<state_arr.length; i++) {
    option_str.options[option_str.length] = new Option(state_arr[i],state_arr[i]);
}
$('#state').parent().children(':not(#state)').remove();
$('#state').selectbox();
}
</script>

<p>
<select id="country" class= "items" name ="country">
<option value="countryCode">Country Name</option>
</select>

Answer 3

<script type="text/javascript" src="scripts/jquery.selectbox-0.5.js"></script>
<script type="text/javascript" src = "scripts/countries2.js"></script>
<script type="text/javascript">
$(document).ready(function(){
    $('.selectBoxMedium').selectboxMedium();
    $('.selectBoxSmall').selectboxSmall();
    $('.selectBoxSmallest').selectboxSmallest();
    $('.selectBox').selectbox();
    $(document).pngFix();

    $('.selectBoxMedium, .selectBoxSmall, .selectBoxSmallest, .selectBox').change(function() {
        alert($(this).attr('class') + ' has changed');
    });

    $('#country').change(function() {
        print_state1('state', $(this+':selected').index());
    });

    print_country1("country");
});
</script>
<p class="formInput formSelectBox">
    <select id="country" class="selectBox data" name="country"></select>
</p>

<p class="formInput formSelectBox">
    <select name="state" id="state" class="selectBox"></select>
</p>

WHAT NOW?