检查 String 是否包含 Java/Android 中的 URL 的最佳方法是什么？

Question

What's the best way to check if a String contains a URL in Java/Android? Would the best way be to check if the string contains |.com | .net |.org |.info |.everythingelse|? Or is there a better way to do it?

The url is entered into a EditText in Android, it could be a pasted url or it could be a manually entered url where the user doesn't feel like typing in http://... I'm working on a URL shortening app.

Answer 1

Best way would be to use regular expression, something like below:

public static final String URL_REGEX = "^((https?|ftp)://|(www|ftp)\\.)?[a-z0-9-]+(\\.[a-z0-9-]+)+([/?].*)?$";

Pattern p = Pattern.compile(URL_REGEX);
Matcher m = p.matcher("example.com");//replace with string to compare
if(m.find()) {
    System.out.println("String contains URL");
}

Answer 2

This is simply done with a try catch around the constructor (this is necessary either way).

String inputUrl = getInput();
if (!inputUrl.contains("http://"))
    inputUrl = "http://" + inputUrl;

URL url;
try {
    url = new URL(inputUrl);
} catch (MalformedURLException e) {
    Log.v("myApp", "bad url entered");
}
if (url == null)
    userEnteredBadUrl();
else
    continue();

Answer 3

After looking around I tried to improve Zaid's answer by removing the try-catch block. Also, this solution recognizes more patterns as it uses a regex.

So, firstly get this pattern:

// Pattern for recognizing a URL, based off RFC 3986
private static final Pattern urlPattern = Pattern.compile(
    "(?:^|[\\W])((ht|f)tp(s?):\\/\\/|www\\.)"
            + "(([\\w\\-]+\\.){1,}?([\\w\\-.~]+\\/?)*"
            + "[\\p{Alnum}.,%_=?&#\\-+()\\[\\]\\*$~@!:/{};']*)",
    Pattern.CASE_INSENSITIVE | Pattern.MULTILINE | Pattern.DOTALL);

Then, use this method (supposing str is your string):

    // separate input by spaces ( URLs don't have spaces )
    String [] parts = str.split("\\s+");

    // get every part
    for( String item : parts ) {
        if(urlPattern.matcher(item).matches()) { 
            //it's a good url
            System.out.print("<a href=\"" + item + "\">"+ item + "</a> " );                
        } else {
           // it isn't a url
            System.out.print(item + " ");    
        }
    }

Answer 4

Based on Enkk's answer, i present my solution:

public static boolean containsLink(String input) {
    boolean result = false;

    String[] parts = input.split("\\s+");

    for (String item : parts) {
        if (android.util.Patterns.WEB_URL.matcher(item).matches()) {
            result = true;
            break;
        }
    }

    return result;
}

Answer 5

Old question, but found this , so I thought it might be useful to share. Should help for Android...

Answer 6

I would first use java.util.Scanner to find candidate URLs in the user input using a very dumb pattern that will yield false positives, but no false negatives. Then, use something like the answer @ZedScio provided to filter them down. For example,

Pattern p = Pattern.compile("[^.]+[.][^.]+");
Scanner scanner = new Scanner("Hey Dave, I found this great site called blah.com you should visit it");
while (scanner.hasNext()) {
    if (scanner.hasNext(p)) {
        String possibleUrl = scanner.next(p);
        if (!possibleUrl.contains("://")) {
            possibleUrl = "http://" + possibleUrl;
        }

        try {
            URL url = new URL(possibleUrl);
            doSomethingWith(url);
        } catch (MalformedURLException e) {
            continue;
        }
    } else {
        scanner.next();
    }
}

Answer 7

If you don't want to experiment with regular expressions and try a tested method, you can use the Apache Commons Library and validate if a given string is an URL/Hyperlink or not. Below is the example.

Please note: This example is to detect if a given text as a 'whole' is a URL. For text that may contain a combination of regular text along with URLs, one might have to perform an additional step of splitting the string based on spaces and loop through the array and validate each array item.

Gradle dependency:

implementation 'commons-validator:commons-validator:1.6'

Code:

import org.apache.commons.validator.routines.UrlValidator;

// Using the default constructor of UrlValidator class
public boolean URLValidator(String s) {
    UrlValidator urlValidator = new UrlValidator();
    return urlValidator.isValid(s);
}

// Passing a scheme set to the constructor
public boolean URLValidator(String s) {
    String[] schemes = {"http","https"}; // add 'ftp' is you need
    UrlValidator urlValidator = new UrlValidator(schemes);
    return urlValidator.isValid(s);
}

// Passing a Scheme set and set of Options to the constructor
public boolean URLValidator(String s) {
    String[] schemes = {"http","https"}; // add 'ftp' is you need. Providing no Scheme will validate for http, https and ftp
    long options = UrlValidator.ALLOW_ALL_SCHEMES + UrlValidator.ALLOW_2_SLASHES + UrlValidator.NO_FRAGMENTS;
    UrlValidator urlValidator = new UrlValidator(schemes, options);
    return urlValidator.isValid(s);
}

// Possible Options are:
// ALLOW_ALL_SCHEMES
// ALLOW_2_SLASHES
// NO_FRAGMENTS
// ALLOW_LOCAL_URLS

To use multiple options, just add them with the '+' operator

If you need to exclude project level or transitive dependencies in the grade while using the Apache Commons library, you may want to do the following (Remove whatever is required from the list):

implementation 'commons-validator:commons-validator:1.6' {
    exclude group: 'commons-logging'
    exclude group: 'commons-collections'
    exclude group: 'commons-digester'
    exclude group: 'commons-beanutils'
}

For more information, the link may provide some details.

http://commons.apache.org/proper/commons-validator/dependencies.html

Answer 8

This function is working for me

private boolean containsURL(String content){
    String REGEX = "\\b(https?|ftp|file)://[-a-zA-Z0-9+&@#/%?=~_|!:,.;]*[-a-zA-Z0-9+&@#/%=~_|]";
    Pattern p = Pattern.compile(REGEX,Pattern.CASE_INSENSITIVE);
    Matcher m = p.matcher(content);
    return m.find();
}

Call this function

boolean isContain = containsURL("Pass your string here...");
Log.d("Result", String.valueOf(isContain));

NOTE:- I have tested string containing single url

Answer 9

You need to use URLUtil isNetworkUrl(url) or isValidUrl(url)

Answer 10

public boolean isURL(String text) {
    return text.length() > 3 && text.contains(".")
            && text.toCharArray()[text.length() - 1] != '.' && text.toCharArray()[text.length() - 2] != '.'
            && !text.contains(" ") && !text.contains("\n");
}

Answer 11

The best way is to to set the property autolink to your textview, Android will recognize, change the appearance and make clickable a link anywhere inside the string.

android:autoLink="web"