如何基于传递给函数的值从javascript中的数据库中获取数据
[英]How to get data from database in javascript based on the value passed to the function
问题描述
In my web application, I want to retrieve data from database based on the value that is passed to the function. 
在我的Web应用程序中，我想基于传递给函数的值从数据库检索数据。 I wrote the query as follows. 我写的查询如下。
<script>
//Functions to open database and to create, insert data into tables
getSelectedRow = function(val)
{
db.transaction(function(transaction) {
transaction.executeSql('SELECT * FROM Employ where number = parseInt(val);',[], selectedRowValues, errorHandler);
});
};
selectedRowValues = function(transaction,results)
{
for(var i = 0; i < results.rows.length; i++)
{
var row = results.rows.item(i);
alert(row['number']);
alert(row['name']);
}
};
</script>
In body tag, 在身体标签中
<body>
---
<a href = "#" onClick = "javascript:getSelectedRow('1')>getValues</a>
I got the problem while retrieving data from database, ie, at SELECT query. 从数据库中检索数据时出现问题，即在SELECT查询中。 It doesn't accept the value parseInt(val), if I give the condition as 'name = 1' it simply accepts the condition and give the result, but it doesn't accept 'name = parseInt(val)' and throws error as 'no such column: val code: 1' Please tell me how to pass value in 'val'.. Thanks in Advance.. 它不接受值parseInt（val），如果我将条件指定为“ name = 1”，则它仅接受条件并给出结果，但不接受“ name = parseInt（val）”并抛出错误如“无此类列：val代码：1”，请告诉我如何在“ val”中传递值。
3 个解决方案
解决方案1
2 已采纳 2012-06-14 06:47:56
'SELECT * FROM Employ where number = ' + parseInt(val, 10) + ';'
例如，如果val为"10"则最终将构建字符串：
"SELECT * FROM Employ where number = 10;"
解决方案2
1 2012-06-14 06:49:56
The error is coming as your query is getting formed as 随着查询的形成，错误即将到来
SELECT * FROM Employ where number = parseInt(val);
I dont know which DB you are using but no DB will understand parseInt . 我不知道您正在使用哪个数据库，但是没有一个数据库会理解parseInt 。
What you can do is use a variable say temp and store the value of parseInt(val) in temp variable and make the query as 您可以做的是使用一个名为temp的变量，并将parseInt(val)的值存储在temp变量中，并使查询为
SELECT * FROM Employ where number = temp;
解决方案3
1 2012-06-14 06:56:34
Try the following: 请尝试以下操作：
<script>
//Functions to open database and to create, insert data into tables
getSelectedRow = function(val)
{
db.transaction(function(transaction) {
transaction.executeSql('SELECT * FROM Employ where number = ?;',[parseInt(val)], selectedRowValues, errorHandler);
});
};
selectedRowValues = function(transaction,results)
{
for(var i = 0; i < results.rows.length; i++)
{
var row = results.rows.item(i);
alert(row['number']);
alert(row['name']);
}
};
</script>
You don't have access to javascript variable names in SQL, you must pass the values to the Database. 您无权使用SQL中的javascript变量名称，必须将值传递给数据库。
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