[英]function declaration inside main and also outside main in C
The first program compiled properly.second gave error saying too few argument for foo... is global declaration ignored by the compiler in both programs? 第一个程序编译得正确。第二个程序给出了错误,说foo的参数太少......编译器在两个程序中都忽略了全局声明?
first program: 第一个程序:
#include<stdio.h>
void foo();
int main()
{
void foo(int);
foo(1);
return 0;
}
void foo(int i)
{
printf("2 ");
}
void f()
{
foo(1);
}
second program: 第二个程序:
void foo();
int main()
{
void foo(int);
foo();
return 0;
}
void foo()
{
printf("2 ");
}
void f()
{
foo();
}
The inner declaration hides declarations at the global scope . 内部声明隐藏了全局范围 内的声明 。 The second program fails because the declaration
void foo(int);
第二个程序失败,因为声明
void foo(int);
hides the global declaration void foo();
隐藏全局声明
void foo();
; ; so when you say
foo
within main
you are referring to the one taking an int
as argument. 所以当你在
main
说foo
时,你指的是以int
为参数的那个。
I see that you investigate the specific behavior of inner declaration but why not: 我看到你调查内部声明的具体行为,但为什么不:
#include<stdio.h>
void foo(int);
int main()
{
foo(1);
return 0;
}
void foo(int i)
{
printf("2 ");
}
void f()
{
foo(1);
}
or even: 甚至:
#include<stdio.h>
void foo(int i)
{
printf("2 ");
}
void f()
{
foo(1);
}
int main()
{
foo(1);
return 0;
}
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