[英]PHP-SQl Autocomplete search
I've writing a code to log in a user and display his various details. 我编写了一个代码来登录用户并显示他的各种细节。 This is working perfectly fine. 这工作得非常好。 On addition to it; 除此之外; I added a autocomplete search that doesn't seem to work. 我添加了一个似乎不起作用的自动完成搜索。 I'm using Jquery's autocomplete. 我正在使用Jquery的自动完成功能。 The fields in the search box are searched from SQL. 搜索框中的字段将从SQL中搜索。
But nothing happens. 但没有任何反应。 I type in the text in the text-field but nothing happens. 我在文本字段中键入文本但没有任何反应。
Here's my whole corrected PHP code (excluding the connection file) 这是我整个更正的PHP代码(不包括连接文件)
<script>
$(document).ready(function() {
$("input#autocomplete").autocomplete({
source: keywordList,
minLength: 1,
});
});
</script>
<?php echo keywordArray(); ?>
<?php function keywordArray()
{
$rsKeywords = mysql_query("SELECT * FROM job");
$output = '<script>'."\n";
$output .= 'var keywordList = [';
while($row_rsKeywords = mysql_fetch_assoc($rsKeywords))
{
$output .= '"'.$row_rsKeywords['work'].'",';
}
$output = substr($output,0,-1); //Get rid of the trailing comma
$output .= '];'."\n";
$output .= '</script>';
return $output;
}
?>
//search script: //搜索脚本:
<?php
if(!isset($_POST['submit'])){
echo "Your search was invalid";
exit;
}
$keyword = mysql_real_escape_string($_POST['keywords']);
$sql = "SELECT * FROM job WHERE work='$keyword' or work LIKE 'ANOTHER_PARAMETER' LIMIT 5";
$result = mysql_query($sql);
$numrows = mysql_num_rows($result);
echo //details etc
>?
Here's my whole corrected PHP code (excluding the connection file) 这是我整个更正的PHP代码(不包括连接文件)
<script>
$(document).ready(function() {
$("input#autocomplete").autocomplete({
source: keywordList,
minLength: 1,
});
});
</script>
<?php echo keywordArray(); ?>
<?php function keywordArray()
{
$rsKeywords = mysql_query("SELECT * FROM job");
$output = '<script>'."\n";
$output .= 'var keywordList = [';
while($row_rsKeywords = mysql_fetch_assoc($rsKeywords))
{
$output .= '"'.$row_rsKeywords['work'].'",';
}
$output = substr($output,0,-1); //Get rid of the trailing comma
$output .= '];'."\n";
$output .= '</script>';
return $output;
}
?>
//search script: //搜索脚本:
<?php
if(!isset($_POST['submit'])){
echo "Your search was invalid";
exit;
}
$keyword = mysql_real_escape_string($_POST['keywords']);
$sql = "SELECT * FROM job WHERE work='$keyword' or work LIKE 'ANOTHER_PARAMETER' LIMIT 5";
$result = mysql_query($sql);
$numrows = mysql_num_rows($result);
echo //details etc
>?
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