在Linux中剪切GREP命令

Question

Okay so i have a variable called search which holds the string "Find this Code - Now". I want to search for that code and if it finds it the system would reply with true or something on those lines, if it doesn't then it just exits the script with error.

I tried to use grep but i couldn't figure out how to cut only what was searched for so i could run an if else statement

Answer 1

您可以使用-q开关并检查grep的退出状态，例如grep -q $var <file> && echo "true" 。

Answer 2

I tried to use grep but i couldn't figure out how to cut only what was searched for so i could run an if else statement

Grep has a switch --only-matching

 -o, --only-matching       show only the part of a line matching PATTERN

Answer 3

> X="not gonna find it"
> grep -qR "$X" .; echo $?
1
> X="Find this Code - Now"
> grep -qR "$X" .; echo $?
0