从动态表单发布（多行）

Question

I have a form that creates form rows (fields) dynamically (add-delete) up to seven. Each additional form row has an incrimental number appended to it (ie: name="product" next is name="product2".. "Product3" etc.). So I thought I would just use isset to see what is posted and only insert what is posted but my lack of skills has led to this not working. See my code below:

    mysql_select_db("inventory", $con);

    $sql="INSERT INTO shipped (id, type, client, product, color, quantity)
    VALUES ('$_POST[productid]','$_POST[type]','$_POST[client]','$_POST[product]','$_POST[color]','$_POST[quantity]')";
    if( isset($_POST['productid2']) ) {
    "INSERT INTO shipped (id, type, client, product, color, quantity)
    VALUES ('$_POST[productid2]','$_POST[type2]','$_POST[client2]','$_POST[product2]','$_POST[color2]','$_POST[quantity2]')";
    }

I planned to just add "isset" for each product but as it turns out this will only insert one of the set of post values and not both. I am going to have up to product7 (so seven inserts at max). Any help?

Answer 1

You would use the array in input fields

<input type="text" name="productid[]" />
<input type="text" name="type[]" />
<input type="text" name="client[]" />
<input type="text" name="product[]" />
<input type="text" name="color[]" />
<input type="text" name="quantity[]" />

At server side:

foreach($_POST['product'] as $k => $v){
   $sql="INSERT INTO shipped (id, type, client, product, color, quantity) VALUES 
       ($_POST['productid'][$k],$_POST['type'][$k],$_POST[client][$k]','$v','$_POST[color][$k]','$_POST[quantity][$k]')";

}

Answer 2

Ok so I did like the other answer as it seemed much more elegant than the solution I ended up using - but the fact is the other answer just did not work. So my solution just ended up just checking if the next form set of form fields is set, and if it is it displays the proper inserts. See the first part here:

mysql_select_db("inventory", $con);

if( !isset($_POST['productid2']) ) {
$sql="INSERT INTO shipped (id, type, client, product, color, quantity)
VALUES ('$_POST[productid]','$_POST[type]','$_POST[client]','$_POST[product]','$_POST[color]','$_POST[quantity]')";
}

if( isset($_POST['productid2']) ) {
$sql="INSERT INTO shipped (id, type, client, product, color, quantity)
VALUES ('$_POST[productid]','$_POST[type]','$_POST[client]','$_POST[product]','$_POST[color]','$_POST[quantity]'),
('$_POST[productid2]','$_POST[type2]','$_POST[client2]','$_POST[product2]','$_POST[color2]','$_POST[quantity2]')";
}

if( isset($_POST['productid3']) ) {
$sql="INSERT INTO shipped (id, type, client, product, color, quantity)
VALUES ('$_POST[productid]','$_POST[type]','$_POST[client]','$_POST[product]','$_POST[color]','$_POST[quantity]'),
('$_POST[productid2]','$_POST[type2]','$_POST[client2]','$_POST[product2]','$_POST[color2]','$_POST[quantity2]'),
('$_POST[productid3]','$_POST[type3]','$_POST[client3]','$_POST[product3]','$_POST[color3]','$_POST[quantity3]')";
}

Like this another four times... adding the other values each time. This works for me because my form fields can only be added a max of seven times so it doesn't need to be infinite. So if you are only allowing a small amount of form fields to be added this will work well.