如何从给定的选项初始化django-form数据类型字段？

Question

First of all: I am not able to find out the proper Title of this question.

Anyhow the question is:

I have to fill a form at template and the fields of this form are user dependent. For example you passes integer (integer is not a datatype) as a parameter to the method and it should returns like this:

fileds = forms.IntegerField()

If you pass bool then it should like this:

fields = forms.BooleanField()

So that i can use them to create my form. I tried with this code but it returns into the form of string.

Some.py file:

choices = (('bool','BooleanField()'),
            ('integer','IntegerField()'))
def choose_field():
   option = 'bool' # Here it is hardcoded but in my app it comes from database.
   for x in choices:
      if x[0]==option:
         type = x[1]
   a = 'forms'
   field = [a,type]
   field = ".".join(field)
   return field

When i print the field it prints 'forms.BooleanField()' . I also use this return value but it didn't work. Amy solution to this problem?

Answer 1

The simpliest way is to create your form class and include fields for all possible choices to it. Then write a constructor in this class and hide the fields you don't want to appear. The constructor must take a parameter indicating which fields do we need. It can be useful to store this parameter in the form and use it in clean method to correct collected data accordingly to this parameter.

class Your_form(forms.ModelForm):
  field_integer = forms.IntegerField()
  field_boolean = forms.BooleanField()

  def __init__(self, *args, **kwargs):
    option = kwargs["option"]
    if option == "integer":
      field_boolean.widget = field_boolean.hidden_widget()
    else:
      field_integer.widget = field_integer.hidden_widget()
    super(Your_form, self).__init__(*args, **kwargs)

In your controller:

option = 'bool'
form = Your_form(option=option)