[英]Regex to match strings starting and ending with %%
I have a text that has multiple occurrences of variables in this format: 我有一个以这种格式出现多次变量的文本:
Example text will %%include%% these %%parameters%%
I'm trying to use this: 我想用这个:
preg_match('/%%[\\s\\S]*?%%/i',$output, $matches);
But for some reason I'm getting only the first match, any ideas? 但出于某种原因,我只得到第一场比赛,任何想法?
使用preg_match_all因为您需要多个匹配项。
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