javascript正则表达式示例-提取字符直到出现？

Question

I have a text like this.

Mr John Smith , Mr James Smith                  +(21)-(21)-12345678, 12345678, 12345678                     +(21)-12345678, 12345678, 12345678        SomeTextHereAlso        +(21)-(22)-12345678                       www.somewebaddress.co.uk                            Some Title, Some Place , Some Town,Some Suburb,  City - 100000

I want to extract each of these strings using regex in javascript. I found some examples and this morning they worked. Now I don't know why they don't work any more.

To extract

Mr John Smith , Mr James Smith

I used this.

/\S(.*)\+/  and /\S(.*?)\+/

This didn't work. I can't figure out why.

To extract this

+(21)-(21)-12345678, 12345678, 12345678                     +(21)-12345678, 12345678, 12345678        SomeTextHereAlso        +(21)-(22)-12345678     

I used this.

/\+(.*)(?=www.)/

This did work.

And for url I used

/www(.*?)(?=\s\s)/

And this works too.

The only problem is the first example that should extract all the characters until the first + but it extracts all the characters until the last +.

I checked on http://gskinner.com/RegExr/?2tr5t and the examples I showed here work. Are there any more similar examples that could help me since I looked into the code and didn't find any error.

If regex is fine then how can I use IndexOf() method for this example to extract what I want?

Answer 1

I used This solution help me solve my problem. So my project will be combination of RegEx and IndexOf() method.

I don't know why RegEx failed on this matter. Thank you all.

Answer 2

Well, for the first example, you could just forbid the inner loop from matching "+" characters, using a negated character class.

/\S([^+]*)\+/

As for extracting the matches, a common pattern is doing something like

var myPattern = /someregex/g;
var match;
while( (match=myPattern.exec(theString)) !== null ){
    console.log('the total match', match[0]);
    console.log('the first grouped parenthesis', match[1]);
    //and so on
}

---

For example, running

var regex = /a(\d+)/g;
var str = ' a100 b200 a300';
var match;
while( (match=regex.exec(str)) !== null ){
    console.log(match)
}

prints

["a100", "100"]
["a300", "300"]

If you have any more doubts, I highly recomend ythe documentation over on MDN

Answer 3

您可以尝试[^+]+或更具体地说^[^+]+