[英]Read lines starting from a line number in a bash script
I'm trying to read a file line by line starting from a specific line in bash. 我正在尝试从bash中的特定行开始逐行读取文件。 I have already used the while command to read each line of the file by incrementing the count. 我已经使用while命令通过递增计数来读取文件的每一行。 Can I make it start from a specific line? 我可以从特定的线开始吗?
let count=0
declare -a ARRAY
while read LINE; do
ARRAY[$count]=$LINE
vech=${ARRAY[$count]}
if [...blah ..]
then
...blah..
fi
sleep 2
((count++))
done < filec.c
Any kind of help in the form of suggestions or algorithms are welcome. 欢迎以建议或算法的形式提供任何形式的帮助。
Edit: I'm trying to pass the line number as a variable . 编辑:我正在尝试将行号作为变量传递。 I am Grepping for a specific pattern and if found, should pass the line number starting from the pattern. 我正在Grepping一个特定的模式,如果找到,应该从模式开始传递行号。
I would use sed
's addresses to start at a particular line number and print to the end of the file: 我会使用sed
的地址从特定的行号开始并打印到文件的末尾:
lineNumber=10
sed -n "$lineNumber"',$p' |
while read line; do
# do stuff
done
Either that or, as Fredrik suggested, use awk
: 或者,正如Fredrik建议的那样,使用awk
:
lineNumber=10
awk "NR > $lineNumber" |
while read line; do
# do stuff
done
What about something like this? 这样的事情怎么样?
while read -r line
do
echo "$line"
done < <(tail -n +number file.name)
It's not POSIX compatible, but try on your Bash. 它不是POSIX兼容的,但试试你的Bash。 Of course, do what you want with $line inside while loop. 当然,在循环中用$ line做你想要的东西。
PS: Change number with yhe number line you want and file.name with the file name. PS:使用您想要的数字行更改数字,使用文件名更改file.name。
Some of the many ways: http://mywiki.wooledge.org/BashFAQ/011 其中一些方法有: http : //mywiki.wooledge.org/BashFAQ/011
Personally: 亲身:
printf '%s\n' {1..6} | { mapfile -ts 3 x; declare -p x; }
Also, don't use all-caps variable names. 另外,不要使用全大写变量名。
Just keep a counter. 只要保持一个柜台。 To print all lines after a certain line, you can do like this: 要在某一行之后打印所有行,您可以这样做:
#!/bin/bash
cnt=0
while read LINE
do
if [ "$cnt" -gt 5 ];
then
echo $LINE
fi
cnt=$((cnt+1))
done < lines.txt
or, why not use awk: 或者,为什么不使用awk:
awk 'NR>5' lines.txt
Just go a read a certain number of lines up to the number you want and start your logic to read the rest. 只需读取一定数量的行,直到你想要的数字,并开始你的逻辑阅读其余的。
There is no way to economize on a "text" file, you can't skip lines without actually reading them. 没有办法节省“文本”文件,你不能跳过行而不实际读取它们。 The lines are delimited by 0x0a and of variable lengths. 这些行由0x0a和可变长度分隔。 Therefore each delimiter must be scanned and counted to reach a certain "line-number". 因此,必须扫描每个分隔符并计数以达到某个“行号”。 There are gimmicks that let you think you didn't read them, but you did. 有噱头可以让你觉得你没有读过它们,但是你做到了。
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