[英]How to replace dates in text file with Powershell using regular expressions
I've done much searching on this and haven't worked out the answer, but I feel like I am close! 我已经做了很多搜索,并没有找到答案,但我觉得我很亲密!
I have dates in a text file in the following format: 18/06/2012 23:00:43 (dd/mm/yyyy HH:MM:SS)
which I want to convert to: 2012-18-06 23:00:43 (yyyy-dd-mm HH:MM:SS)
using Powershell. 我在文本文件中的日期格式如下:
18/06/2012 23:00:43 (dd/mm/yyyy HH:MM:SS)
我要转换为: 2012-18-06 23:00:43 (yyyy-dd-mm HH:MM:SS)
使用Powershell。
To perform the conversion in a text editor using regular expressions I would do this: 要使用正则表达式在文本编辑器中执行转换,我会这样做:
Find: ([0-9]+)/+([0-9]+)/+([0-9]+)
Replace with: \3-\2-\1
So I have tried using this same logic in a the following Powershell script: 所以我尝试在以下Powershell脚本中使用相同的逻辑:
(Get-Content C:\script\test.txt) |
Foreach-Object {$_ -replace "([0-9]+)/+([0-9]+)/+([0-9]+)", "(\3-\2-\1)"} |
Set-Content C:\script\test.txt
but that results in the following undesired change: 但这导致以下不希望的变化:
\\3-\\2-\\1 23:00:43
\\ 3- \\ \\ 2- \\ 1 23:00:43
Can anybody help me nail this? 任何人都可以帮我解决这个问题吗?
Many thanks in advance! 提前谢谢了!
This is what you want: 这就是你想要的:
(Get-Content C:\script\test.txt) |
Foreach-Object {$_ -replace "([0-9]+)/+([0-9]+)/+([0-9]+)", '$3-$2-$1'} |
Set-Content C:\script\test.txt
Capturing group references are done with the $
symbol, not a backslash. 使用
$
符号捕获组引用,而不是反斜杠。 Also, to reference a captured group by number, you must use single quotes around the replacement string ; 此外,要按编号引用捕获的组, 必须在替换字符串周围使用单引号 ; otherwise, PowerShell will interpret any
$
symbol as a reference to a previously defined variable, which in this case will result in the string "--"
since no such variables exist. 否则,PowerShell会将任何
$
符号解释为对先前定义的变量的引用,在这种情况下将导致字符串"--"
因为不存在这样的变量。
The -replace operator supports the same replacement text placeholders as the Regex.Replace() function in .NET. -replace运算符支持与.NET中的Regex.Replace()函数相同的替换文本占位符。 Eg $& is the overall regex match, $1 is the text matched by the first capturing group, and ${name} is the text matched by the named group "name" .
例如$&是整个正则表达式匹配,$ 1是第一个捕获组匹配的文本,$ {name}是命名组“name”匹配的文本 。
Instead of "(\\3-\\2-\\1)"
use '($3-$2-$1)'
而不是
"(\\3-\\2-\\1)"
使用'($3-$2-$1)'
'06/18/2012 23:00:43' -replace "(\\d+)/(\\d+)/(\\d+)", '($3-$2-$1)'
尝试
Foreach-Object {$_-replace "([0-9]+)/+([0-9]+)/+([0-9]+)", '$3-$2-$1'}
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