显示所有mySQL表中的数据

Question

I have a ton of tables that vary in columns by a small amount. I want to be able to select all the data from every table and just display null values (or blanks) when one table doesn't have a column from another table.

I know this can normally be done using the JOIN operator when you have tables that have relationships between each other, but my tables have no relationships between each other except that they have a lot of common column names.

Answer 1

无论如何，这是我能想到的最接近的东西： 小提琴 。

Answer 2

SELECT DISTINCT TABLE_NAME FROM INFORMATION_SCHEMA.columns
 WHERE TABLE_SCHEMA = 'database_name'
 ORDER BY TABLE_NAME 

This gives you list of all table names. You can then run queries on all of those.