无论字符串中出现的吐出字符数是多少，Javascript都会拆分为2个部分

Question

I want to split a string in Javascript using split function into 2 parts.

For Example i have string:

str='123&345&678&910'

If i use the javascripts split, it split it into 4 parts. But i need it to be in 2 parts only considering the first '&' which it encounters.

As we have in Perl split, if i use like:

($fir, $sec) = split(/&/,str,2)

it split's str into 2 parts, but javascript only gives me:

str.split(/&/, 2);
fir=123
sec=345

i want sec to be:

sec=345&678&910

How can i do it in Javascript.

Answer 1

var subStr = string.substring(string.indexOf('&') + 1);

View this similar question for other answers:

split string only on first instance of specified character

Answer 2

You can use match instead of split :

str='123&345&678&910';
splited = str.match(/^([^&]*?)&(.*)$/);
splited.shift();
console.log(splited);

output:

["123", "345&678&910"]

Answer 3

You can remain on the split part by using the following trick:

var str='123&345&678&910',
    splitted = str.split( '&' ),
    // shift() removes the first item and returns it
    first = splitted.shift();

console.log( first ); // "123"
console.log( splitted.join( '&' ) ); // "345&678&910"

Answer 4

I wrote this function:

function splitter(mystring, mysplitter) {
    var myreturn = [],
        myindexplusone = mystring.indexOf(mysplitter) + 1;

    if (myindexplusone) {
        myreturn[0] = mystring.split(mysplitter, 1)[0];
        myreturn[1] = mystring.substring(myindexplusone);
    }

    return myreturn;
}

var str = splitter("hello-world-this-is-a-test", "-");

console.log(str.join("<br>"));
//hello
//world-this-is-a-test​​​

The output will be either an empty array (not match) or an array with 2 elements (before the split and everything after)

Demo

Answer 5

I have that:

var str='123&345&678&910';
str.split('&',1).concat( str.split('&').slice(1).join('&') );
//["123", "345&678&910"]



str.split('&',2).concat( str.split('&').slice(2).join('&') );
//["123", "345", "678&910"];

for convenience:

String.prototype.mySplit = function( sep, chunks) {
   chunks = chunks|=0 &&chunks>0?chunks-1:0;
   return this.split( sep, chunks )
              .concat( 
                  chunks?this.split( sep ).slice( chunks ).join( sep ):[]
               );
}

Answer 6

What about the use of split() and replace() ?:

Given we have that string str='123&345&678&910' We can do

    var first = str.split("&",1); //gets the first word
    var second = str.replace(first[0]+"&", ""); //removes the first word and the ampersand

Please note that split() returns an array that is why getting the index with first[0] is recommended , however, without getting the index, it still worked as needed ie first+"&" .

Feel free to replace the "&" with the string you need to split with.

Hope this helps :)