[英]AWK - Using RT when RS is a regexp gives me the RS of the next match not the current
I am trying to use gawk to extract paragraphs from a log and it is working perfectly up to the point where I want to include the record separator it found. 我正在尝试使用gawk从日志中提取段落,并且在我要包括发现的记录分隔符的情况下,它工作得非常好。
This is the command: 这是命令:
gawk --re-interval 'BEGIN{RS="[0-9]{1,2}:[0-9]{1,2}:[0-9]{1,2}.[0-9]{1,6} \\[[A-Z]*\\]";} /983a99f8-bec6-11e1-80dd-059a821d0b73/ {print $0}' full.log
If I add in print RT, $0, it prints the RT of the next match not the current match. 如果我在打印RT中添加$ 0,它将打印下一个匹配项而不是当前匹配项的RT。
This is some sample text 这是一些示例文本
9:08:06.899627 [DEBUG] <0.30065.3>@agent:1565 Recs to loop through: [{agent_state,"OpenAcdAgent43","Jeff",
undefined,wrapup,
{call,"983a99f8-bec6-11e1-80dd-059a821d0b73",
voice,
{"8501112234","MorganGrimes"},
"9201",<0.30392.3>,[],
{client,"8221314","DCF",[],1340629596,
1340629596},
[creole_general],
<0.30398.3>,outband,inband,inbound,10},
1340629658,undefined,"Default",1340629658
9:08:06.899707 [INFO] <0.168.0>@cpx_monitor:649 Down message for reference #Ref<0.0.16.137225> of <0.30064.3> due to normal
What I want to be 9:08:06.899627 [DEBUG] able to do is prepend 9:08:06.899627 [DEBUG] to my match but RS takes that away. 我想要成为9:08:06.899627 [DEBUG]能够做的是将9:08:06.899627 [DEBUG]放在我的比赛前面,但RS取消了。 I get 9:08:06.899707 [INFO] instead. 我得到9:08:06.899707 [INFO]代替。
Thanks! 谢谢!
That's because a record separator comes at the end of a record. 这是因为记录分隔符位于记录的末尾 。 So 9:08:06.899627 [DEBUG]
is the end of an empty record and 9:08:06.899707 [INFO]
is the end of the record that matches your GUID regex. 因此9:08:06.899627 [DEBUG]
是空记录的结尾,而9:08:06.899707 [INFO]
是与GUID正则表达式匹配的记录的结尾。
You need to save the previous RT
and output the saved one. 您需要保存前一个RT
然后输出保存的RT
。
gawk --re-interval 'BEGIN{RS="[0-9]{1,2}:[0-9]{1,2}:[0-9]{1,2}.[0-9]{1,6} \\[[A-Z]*\\]";} /983a99f8-bec6-11e1-80dd-059a821d0b73/ {print savedRT, $0} {savedRT = RT}' full.log
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