Oracle SQL - 在字段中查找特殊的非数字字符

Question

如何识别在 where 子句中除了数字之外还有其他任何内容的数据？

Answer 1

SELECT *
  FROM <table>
 WHERE REGEXP_LIKE(<column>, '[^[:digit:]]');

Hope it helps...

Answer 2

You can also use the TRANSLATE function to do this, as follows:

SELECT *
  FROM A_TABLE a
  WHERE LENGTH(TRANSLATE(a.FIELD, 'x0123456789', 'x')) IS NOT NULL

The expression LENGTH(TRANSLATE(a.FIELD, 'x0123456789', 'x')) will return NULL if the field contains only numeric characters. If non-numeric characters are present it will return the number of non-numeric characters.

Share and enjoy.

Answer 3

Try this

SELECT *
FROM table
WHERE regexp_like(column_name,'[^0-9]+');`

This will pick all those rows which have non numeric characters in the column.

For details check this page .

Answer 4

OR this one

select * from <YOUR_TABLE>
where LENGTH(REPLACE(TRANSLATE(<YOUR_TABLE.your_column_name>,
                               ’0123456789′, ‘@@@@@@@@@@’), ‘@’, NULL)) > 0;

Answer 5

While not perfect (doesn't account for characters like '#', '@', etc.) a quick and dirty solution is:

SELECT * FROM <YOUR_TABLE>
WHERE UPPER(<YOUR_TABLE.your_column_name>) = LOWER(<YOUR_TABLE.your_column_name>) 

Answer 6

you could use Translate and filter out the values which have non numeric characters and then order on the columns.

select * from (
    select case  WHEN trn > 0 then NULL  else fld1 end New_column, fld1,trn FROM 
        (
        SELECT '123ab' fld1, LENGTH(TRIM(TRANSLATE('123ab', ' +-.0123456789',' '))) trn FROM dual UNION ALL
        SELECT 'a123b', LENGTH(TRIM(TRANSLATE('a123b', ' +-.0123456789',' '))) FROM dual UNION ALL
        SELECT '1256.54', LENGTH(TRIM(TRANSLATE('1256.54', ' +-.0123456789',' '))) FROM dual UNION ALL
        SELECT '4567899', LENGTH(TRIM(TRANSLATE('4567899', ' +-.0123456789',' '))) FROM dual UNION ALL
        SELECT '-56',LENGTH(TRIM(TRANSLATE ('-56', ' +-.0123456789',' '))) FROM dual
        )
)order by new_column