返回相同控制器的不同视图时，URL保持不变

Question

I am trying to return a different view from my controller. However, although the correct view is displayed the URL stays same.

This is my form in /Company/Create view.

@using (Html.BeginForm("Create", "Company", FormMethod.Post)) 
{ 
 // Form here
}

So basically, the form and model is submitted to /Company/Create action. If the submitted model is valid, then I process the data and redirect to /Company/Index view with

return View("Index");

As I said, correct view is displayed however, URL (address bar) is still http://.../Company/Create

I tried RedirectToAction("Index"); It does not work also. And I do not think its a good MVC practice. I have a single layout and Company views are rendered with RenderBody()

Any ideas ?

Thanks.

Edit :

This is my action method,

[HttpPost]
public ActionResult Create(CompanyCreate model)
{
    /* Fill model with countries again */
    model.FillCountries();

    if (ModelState.IsValid)
    {
        /* Save it to database */
        unitOfWork.CompanyRepository.InsertCompany(model.Company);
        unitOfWork.Save();
        RedirectToAction("Index");
        return View();
    }

    // If we got this far, something failed, redisplay form
    return View(model);
}

Answer 1

You need to redirect to another action if you want the url changed.

However RedirectToAction doesn't redirect instantly but returns a RedirectToRouteResult object which is an ActionResult object.

So you just need to return the result of RedirectToAction from your action:

[HttpPost]
public ActionResult Create(CompanyCreate model)
{
    /* Fill model with countries again */
    model.FillCountries();

    if (ModelState.IsValid)
    {
        /* Save it to database */
        unitOfWork.CompanyRepository.InsertCompany(model.Company);
        unitOfWork.Save();
        return RedirectToAction("Index");
    }

    // If we got this far, something failed, redisplay form
    return View(model);
}