[英]ajax request hidden fields
I'm developing a site (only for fun and learn programming with jquery) and i'd like to know what's wrong with this : 我正在开发一个网站(仅出于娱乐目的,并学习使用jquery编程),我想知道这是怎么回事:
$(window).unload(function(){
var myid = $('input#v1').attr('value'); // hidden
var playauth = $('input#v2').attr('value'); // hidden
var srvid = $('input#v3').attr('value'); // hidden
var result = 'myid='+ myid +'&auth='+ playauth +'&srvid='+ srvid;
$.ajax({
type: "GET",
data: result,
url: "closing.php",
complete: function(data) {
alert(data.responseText);
}
});
});
I'm trying to update a database table. 我正在尝试更新数据库表。 When i close the window nothing happens.
当我关闭窗户时,什么也没发生。 With a previous version of this function :
使用此功能的先前版本:
window.onunload = function () {
var xhReq = new XMLHttpRequest();
var n = document.getElementById("v1").InnerHTML;
var o = document.getElementById("v2").InnerHTML;
var p = document.getElementById("v3").InnerHTML;
xhReq.open("GET", ("closing.php?myid=" + n + "&auth=" + o + "&srvid=" + p) , false);
xhReq.send(null);
var serverResponse = xhReq.responseText;
alert(serverResponse);
};
.. i saw the response alert but GET values were 'undefined'. ..我看到了响应警报,但GET值未定义。 .... probably because the type of inputs is hidden..?
....可能是因为输入的类型是隐藏的..? This is my form... maybe i miss something ??
这是我的表格...也许我错过了什么? I'm really new to jquery/ajax .. please help!!
我真的是jquery / ajax的新手..请帮助!!
<form method="get">
<input id="v1" type="hidden" name="val1" class="aget" value="<?php echo $_GET['myid']; ?>" />
<input id="v2" type="hidden" name="val2" class="bget" value="<?php echo $_GET['playauth']; ?>" />
<input id="v3" type="hidden" name="val3" class="cget" value="<?php echo $_SESSION['srvid']; ?>" />
</form>
change 更改
var myid = $('input#v1').attr('value'); // hidden
var playauth = $('input#v2').attr('value'); // hidden
var srvid = $('input#v3').attr('value'); // hidden
to 至
var myid = $('input#v1').val(); // hidden
var playauth = $('input#v2').val(); // hidden
var srvid = $('input#v3').val(); // hidden
You must use 您必须使用
.val();
instead of .attr('value');
而不是
.attr('value');
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