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获取最后插入值的ID

[英]Getting an ID for the last inserted value

I am trying to get the unique ID for the most recently added value to the database. 我正在尝试获取数据库最近添加的值的唯一ID。 I tried using LastInsertID bu I believe this is not compatible with MySQL (http://www.php.net/manual/en/pdo.lastinsertid.php). 我尝试使用LastInsertID,但我认为这与MySQL(http://www.php.net/manual/zh/pdo.lastinsertid.php)不兼容。

$sql = "INSERT INTO discussion_links (link_url, link_title, link_source, publish_date, link_side, img_link) VALUES (?, ?, ?, ?, ?, ?)";
$sth=$db->prepare($sql);
$sth->execute(array($_POST['OP_link_url'], $_POST['OP_title'], $_POST['OP_source'], $_POST['OP_pub_date'], $_POST['OP_disc_side'], $_POST['OP_img_url']));
$op_link_id = $sth->$db->lastInsertID();

Here I get the error: PHP Catchable fatal error: Object of class PDO could not be converted to string 在这里,我得到了错误:PHP可捕获的致命错误:PDO类的对象无法转换为字符串

I also tried doing that last line as: 我还尝试将最后一行作为:

$op_link_id = $sth->fetch(PDO::lastInsertID);

And

$temp = $sth->fetch(PDO::FETCH_ASSOC);
$temp_op_link_id = $temp['link_id'];

But neither one worked (got some SQLState General Error 2053). 但是,没有一个有效(得到了一些SQLState General Error 2053)。

Thanks, 谢谢,

lastInsertID() should be called on PDO instance. 应该在PDO实例上调用lastInsertID()

$op_link_id = $sth->$db->lastInsertID();

Should be 应该

$op_link_id = $db->lastInsertID();

尝试这个

$op_link_id = $db->lastInsertID();

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