如何遍历每个列表项的列表评估第一个字符

Question

Problem: How do I loop through a list, look at the first char in each list item. If the first char = "0" then remove the "0" then look at next item in list for same evaluation. else: leave it as is.

Code thus far:

gList = ["094G.016", "094G.019", "094G.005", "194G.015"]

for x in gList:
    lGrid[i].lstrip("0")
    print gList
else:
    pass

Desired Output:

gList = ["94G.016", "94G.019", "94G.005", "194G.015"]

Research:

I can use gList.lstrip("0") to remove the zero from the first item in the list but don't know how to get it to move to the next entry and repeat the process.

Alternatively: I know I can use gList[0][0] to select the first list/char item but again need way for it to loop through the list.

EDIT: Using a generator:

Code thus far:

def rem0(data):
    (x.lstrip('0') for x in lGrid)
    yield x

for i in rem0(lGrid):
    print i

Desired Output:

gList = ["94G.016", "94G.019", "94G.005", "194G.015"]

Answer 1

>>> gList = ["094G.016", "094G.019", "094G.005", "194G.015"]
>>> [x.lstrip('0') for x in gList]
['94G.016', '94G.019', '94G.005', '194G.015']

improving your approach: with every iteration x points to the current item, so apply lstrip() on x not on gList

using item:

for x in gList:  
    x.lstrip("0") 

using index :

for index in xrange(len(gList)):   #xrange() or(range() in python 3.x) returns a iterable which contains values from 0 to len(gList)-1 
    gList[index].lstrip("0")

Answer 2

Check out the beauty of list comprehensions on python docs.

A solution would be

Removing the item:

[item for item in gList if item[0] != '0']

or removing the leading '0'

[item.lstrip('0') for item in gList]

Updated answer, since I cannot post comments.

Answer 3

To fix your code:

gList = ["094G.016", "094G.019", "094G.005", "194G.015"]

outL=[]
for x in gList:
    outL.append(x.lstrip("0"))

print outL
# prints ['94G.016', '94G.019', '94G.005', '194G.015']

As others have said, this is easier with a list comprehension:

>>> [x.lstrip('0') for x in gList]
['94G.016', '94G.019', '94G.005', '194G.015']

Or, better still, a generator:

>>> (x.lstrip('0') for x in gList)
<generator object <genexpr> at 0x10c27c140>
>>> list(_)
['94G.016', '94G.019', '94G.005', '194G.015']

Edit

You can do a generator two ways easily.

First is to write a function:

def rem0(data):
    for x in data:
       yield x.lstrip('0')

for i in rem0(gList):
   print i

The other is a gen expression right where you need it:

for i in (x.lstrip('0') for x in gList): 
   print i

Or even:

g=(x.lstrip('0') for x in gList)
for i in g:
    ...

Both ways print your desired output.