创建带有参数的网址，并将其用于其他gsp页面grails groovy

Question

I would like to dynamically create a link with some parameters to a page where those values would be used:

<td><a href="${createLink(controller:'display', action="viewer", params: ['file' : '${stream.file}', 'media' : '${stream.media}'])}">${fieldValue(bean: streamInstance, field: "media")}</a></td>

In my viewer.gsp I want to be use those values in a link that displays a video stream:

<source src="path/to/my/videodir/${media}" type='video/mp4'></source>

But I'm not having much success so far :-(. Could someone please help me on that?

Answer 1

i see a few places where there should be semicolons instead of equals, and single quotes instead of double quotes

${createLink(controller:'display', action:'viewer', params:'[file : "${stream.file}", media : "${stream.media}']")}

my only other thoughts is that if the stream.file variables don't display their value, then try escaping the double quotes /" and if that doesn't work then try removing the ${} around stream.file and stream.media since they are already inside an EL block

Answer 2

This worked for me...

<g:set var="myarray" value="[file: stream.file, media: stream.media]" />
<a href="${createLink(controller:'display', action:'viewer', params:myarray)}">
  ${fieldValue(bean: streamInstance, field: "media")}
</a>