[英]shell_exec in PHP returns empty string
shell_exec
and exec
are not returning any content. shell_exec
和exec
不返回任何内容。 I can't figure out what's wrong. 我不知道怎么了。
Here's some code: 这是一些代码:
echo 'test: ';
$output = shell_exec('whoami');
var_export($output, TRUE);
echo PHP_EOL . '<br>' . PHP_EOL;
And here's the source of the output 这是输出的来源
test 2:
<br>
I do not have control over the host, but I believe they're running SuPHP. 我无法控制主机,但我相信它们正在运行SuPHP。 According to
phpinfo
, safe_mode is off. 根据
phpinfo
,safe_mode关闭。 Running whoami
from SSH outputs the expected value. 通过SSH运行
whoami
输出预期值。
I'm at a loss. 我很茫然。 Any idea how to debug this?
知道如何调试吗?
You're never printing the $output
variable. 您永远不会打印
$output
变量。 The var_export()
call returns the content of the variable when you call it with a true
second parameter, it does not print it directly. 当您使用
true
第二个参数调用var_export()
调用时, 将返回变量的内容,但不会直接打印该变量。
If you want the output from a shell command read back into PHP, you're probably going to need popen()
. 如果要将shell命令的输出读回PHP,则可能需要
popen()
。 For example: 例如:
if( ($fp = popen("some shell command", "r")) ) {
while( !feof($fp) ) {
echo fread($fp, 1024);
flush(); // input will be buffered
}
fclose($fp);
}
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