Qemu arm Linux内核启动调试，没有源代码

Question

I am using Qemu to learn some linux kernel development/hacking and wanted to debug the boot process of Linux (2.6.34.3). I have compiled for the ARM versatile platform and is using Codesourcerys arm-none-eabi crosscompiler. I am using Eclipse as the environment to build and debug using gdbserver.

So I have manged to successfully build and run the kernel in qemu but the problem is that I dont see any source code in the debugger at the boot process (at address 0), I can only see the disassembly code. However, when it switches to virtual memory at init/main.c (address over 0xC0000000), the source code appears and I can see the source code and step through and over code. Why is that? I want that from the beginning.

Anyone have any tips on how to debug the boot process of Linux? All the guides in google shows how to debug the kernel, but they all show from start_kernel() (located in init/main.c ) and not from the beginning of the boot process (in arch/arm/boot/compressed/head.S ). Anyone with experience help please, thank you!

Looked into the System.map in the root folder and there is only symbols for stuff from c0004000 (where the virtual address start). I load vmlinux into gdbserver to get debug information, Maybe thats why theres no source?

Answer 1

The Linux kernel uses a 2-step booting processing (and this does not include any boot loader like u-Boot ...). You can better understand this especially by looking into 2 .lds files (detailed below) for linking:

1. arch/arm/boot/compressed/vmlinux.lds.in , which generates arch/arm/boot/compressed/vmlinux.lds .

   Along with other .o files in arch/arm/boot/compressed , a vmlinux is generated inside this folder.

   You can use arm-none-eabi-nm -a -n arch/arm/boot/compressed/vmlinux to see the symbols for this stage. All addresses are physical addresses.

   These symbols are NOT included in System.map

2. The second vmlinux is generated by kernel .o files and arch/arm/kernel/vmlinux.lds (note: the path is different)

I hope this explains why you can not see the booting source code in Eclipse.

Answer 2

linux kernel is too complex to understand(for a beginner).
Why dont use use a smaller OS like xv6 :

OS is small, sourcecode is about 8000 lines
used by many universities
based on V6(unix),
boot process is the same except that its less complicated than that of linux.
Appendix B of the xv6 book deals with boot process(its short and sweet).You can run gdb on qemu and see the boot process, the main files to check out for are bootasm.S(in assembler) and bootmain.c.

This is much simpler and easier to do and understand when compared to linux.(atleast for beginners).There are assingmennts on , setting up qemu , using gdb ,tracking the boot process , doing changes to the source code etc in the link given.Give it a shot :)

Cheers,
sharan

Answer 3

head.S是用汇编语言编写的，而不是C.这就是.S后缀表示的内容。