[英]Replace dot in middle of a string
Let's say we have an array (new line separated) like: 假设我们有一个数组(用新行分隔):
hello
example.com
test.
something.
aspacefront
test
test.us
to be an array 成为一个数组
hello
example(dot)com.
test.
something.
aspacefront
test
test(dot)us
Can this be done with a regex? 可以用正则表达式完成吗?
What I've up to loop the array then replace to (dot) with this regex \\b[^a-zA-Z\\40]\\b.
我要循环的数组,然后用此正则表达式\\b[^a-zA-Z\\40]\\b.
替换为(点) \\b[^a-zA-Z\\40]\\b.
but it will be example(dot)om rather then example(dot)com. 但是它将是example(dot)om,而不是example(dot)com。
The simplest solution: 最简单的解决方案:
result = subject.replace(/\b\.\b/g, "(com)");
This means "Replace a dot only if it is preceded and followed by an alphanumeric character". 这意味着“仅当在圆点之前和之后带有字母数字字符时才替换圆点”。
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