在上传时获取所有文件名在数组中的PHP
[英]on upload get all file names in array in php
问题描述
What i want to know is how can I get a list [specifically array] of all the files name in a directory when I select it through upload button, after which I would upload that array of files to the database. 
我想知道的是，当我通过上载按钮选择目录时，如何获取目录中所有文件名的列表（特别是数组），然后将其上传到数据库中。 As one file as a single entry. 作为一个文件作为单个条目。 So how do I do that? 那我该怎么做呢？ No to forget that I just need files names and I have to upload these names only not the actual files. 别忘了，我只需要文件名，而我只需要上传这些名称而不是实际文件。
4 个解决方案
解决方案1
1 2012-07-11 18:32:08
If you are using ftp, this function will return all of the filenames of a directory in an array. 如果使用的是ftp，则此函数将返回数组中目录的所有文件名。
function ftp_searchdir($conn_id, $dir) {
if(!@ftp_is_dir($conn_id, $dir)) {
die('No such directory on the ftp-server');
}
if(strrchr($dir, '/') != '/') {
$dir = $dir.'/';
}
$dirlist[0] = $dir;
$list = ftp_nlist($conn_id, $dir);
foreach($list as $path) {
$path = './'.$path;
if($path != $dir.'.' && $path != $dir.'..') {
if(ftp_is_dir($conn_id, $path)) {
$temp = ftp_searchdir($conn_id, ($path), 1);
$dirlist = array_merge($dirlist, $temp);
}
else {
$dirlist[] = $path;
}
}
}
ftp_chdir($conn_id, '/../');
return $dirlist;
}
解决方案2
1 已采纳 2012-07-11 18:34:02
are the files on the server? 文件在服务器上？ if you hopping to have a button you click on browser and open a folder on the end user this will not work. 如果您希望有一个按钮，请单击浏览器并在最终用户上打开一个文件夹，这将不起作用。 most browsers only allow single file selection 大多数浏览器只允许选择单个文件
解决方案3
1 2012-07-11 18:37:22
<?
if (isset($_POST[submit])) {
$uploadArray= array();
$uploadArray[] = $_POST['uploadedfile'];
$uploadArray[] = $_POST['uploadedfile2'];
$uploadArray[] = $_POST['uploadedfile3'];
foreach($uploadArray as $file) {
$target_path = "upload/";
$target_path = $target_path . basename( $_FILES['$file']['name']);
if(move_uploaded_file($_FILES['$file']['tmp_name'], $target_path)) {
echo "The file ". basename( $_FILES['$file']['name']).
" has been uploaded";
} else{
echo "There was an error uploading the file, please try again!";
}
}
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1" />
<title>Untitled Document</title>
</head>
<body>
<form enctype="multipart/form-data" action="upload-simple.php" method="POST">
<p>
<input type="hidden" name="MAX_FILE_SIZE" value="100000" />
Choose a file to upload:
<input name="uploadedfile" type="file" />
</p>
<p>Choose a file to upload:
<input name="uploadedfile2" type="file" />
</p>
<p>Choose a file to upload:
<input name="uploadedfile3" type="file" />
<input name="submit" type="submit" id="submit" value="submit" />
</p>
</form>
</body>
</html>
This Might be Solve your Problems 这可能会解决您的问题
解决方案4
0 2012-07-11 18:30:37
If the files already exist on the server you can use glob 如果文件已经存在于服务器上，则可以使用glob
$files = glob('*.ext'); // or *.* for all files
foreach($files AS $file){
// $file is the name of the file
}
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