[英]String pointer behaviour I am trying to understand
I have written a replacechar function which replaces an instance of a source char with a replacement char. 我已经编写了replacechar函数,该函数用替换char替换了源char的实例。 The function works in that the string is changed as expected but when I attempt to use the return value of the function, puts just outputs a blank line.
该函数的工作原理是按预期方式更改了字符串,但是当我尝试使用该函数的返回值时,put仅输出一个空行。
Can someone please explain what is happening and what I would need to change in replacechar to fix. 有人可以解释一下正在发生的事情以及我需要在replacechar中进行更改以解决的问题。
#include <stdio.h> /* puts */
#include <string.h> /* strcpy */
#include <stdlib.h> /* malloc, free */
char* replacechar(char* s, char ch1, char ch2) {
while (*s) {
if (*s == ch1)
*s = ch2;
*s++;
}
return s;
}
int main()
{
char* s = malloc(8);
strcpy(s, "aarvark");
puts(replacechar(s, 'a', 'z')); /* prints blank line */
puts(s); /* prints zzrvzrk as expected */
free(s);
return 0;
}
Thanks for all the responses. 感谢您的所有回复。
I have changed to this (which now works fine). 我已更改为此(现在可以正常工作)。
char* replacechar(char* s, char ch1, char ch2) {
char* p = s;
while (*p) {
if (*p == ch1)
*p = ch2;
p++;
}
return s;
}
It returns the value of the s
pointer once it's been incremented past the end of the string. 一旦它的值增加到字符串末尾,它将返回
s
指针的值。 Make a local variable in replacechar()
, and increment it, and return the original value of s
. 在
replacechar()
一个局部变量,并将其递增,然后返回s
的原始值。
Thats because the while
loop in replacechar
increment s
until it's \\0
. 那是因为
replacechar
的while
循环将s
递增至\\0
。 At the end of the function you're returning the pointer, which points to \\0
and printing \\0
is a blank line. 在函数的最后,您将返回指向
\\0
的指针,并打印\\0
为空行。 You should manage it like this: 您应该这样管理:
char *replacechar(char *s, char ch1, char ch2) {
char *start = s;
...
return start;
}
Your issue here, with otherwise pretty nice looking code, is one of variable scope. 您这里的问题,加上其他相当漂亮的代码,是可变范围之一。
Use a different local char* within replacechar, like 在replacechar中使用其他本地char *,例如
char* replacechar(char* s, char ch1, char ch2) {
char* tmpstr;
tmpstr=s;
while (*tmpstr) {
if (*tmpstr == ch1)
*tmpstr = ch2;
tmpstr++; /* Note, no "*" here as in your code. */
}
return s; /* s has remained unchanged */
}
#include <stdio.h> /* puts */
#include <string.h> /* strcpy */
#include <stdlib.h> /* malloc, free */
char* replacechar(char* s, char ch1, char ch2) {
char* t = s;
while (*s) {
if (*s == ch1)
*s = ch2;
*s++;
}
return t;
}
int main()
{
char* s = malloc(8);
strcpy(s, "aarvark");
puts(replacechar(s, 'a', 'z')); /* prints blank line */
puts(s); /* prints zzrvzrk as expected */
free(s);
return 0;
}
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