复制构造函数中的C ++用户定义成员

Question

class A
{
std::string name;
public:
A(const A & rhs)
{
name = rhs.name;
}
};

In copy constructor of class A above, will the assignment operator of string class is called or copy constructor of string class?

name data member is not defined yet, so wouldn't the copy constructor be called?

Answer 1

Assignment operator. If you want copy constructor:

A(const A& rhs)
: name(rhs.name)
{
}

Answer 2

将调用默认的（编译器生成的）赋值运算符，该运算符将按成员进行赋值