调用与本地变量同名的函数

Question

I have the following code...

var firstPlay = 1;
if (firstPlay == 1) {
    firstPlay();
}

When I remove the if statement and just put

 firstPlay();

Then it works but with the if statement it doesn't.

Did I make a typo? If not how can I go about debugging this problem?

Answer 1

You are setting the variable firstPlay to the value 1, you can't run a value... use different names for your variables.

Such as:

var firstPlayTest = 1;
if (firstPlayTest == 1) { firstPlay(); }​

Answer 2

A previous function definition of function firstPlay() is replaced/redefined by the numerical value 1. In the following code

        function firstPlay() {alert("firstPlay");}
        alert(firstPlay);
        var firstPlay = 1;
        alert(firstPlay);

the first alert shows a function definition while the second alert shows "1".