在其中使用NOT的MySQL查询，可能吗？

Question

I have a database of order status' and I'd like to return the amount of rows for which the value of that row is anything but Complete.

How would I go about this? I have the following which shows how much rows has 'New' as the status for the order. But I'd like to show all rows except ones with the od_status of Complete.

<?php
$query = "SELECT od_status FROM tbl_order WHERE od_status = 'New'"; 
$result = mysql_query($query) or die(mysql_error());
$num_rows = mysql_num_rows($result);
echo "$num_rows";
?>

Answer 1

<?php
$query = "SELECT od_status FROM tbl_order WHERE od_status != 'Complete'"; 
$result = mysql_query($query) or die(mysql_error());
$num_rows = mysql_num_rows($result);
echo "$num_rows";
?>

Answer 2

$query = "SELECT od_status FROM tbl_order WHERE od_status <> 'Complete'"; 

Answer 3

$query = "SELECT COUNT(*) FROM tbl_order WHERE od_status != 'Complete'";
$result = mysql_query($query);
var_dump($result);

COUNT to count rows and != to select where is not equal to Complete.