[英]C: Define an array of long as return type of function
in C# I would just do: 在C#我会这样做:
private long[] myMethodName()
{
//etc
}
What is the equivalent in C? C中的等价物是什么?
This gives an error: 这给出了一个错误:
long[] readSeqFile(char *fileName)
long *readSeqFile(char *filename);
You might want to make filename
const: 您可能想要使
filename
名为const:
long *readFileName(const char *const filename);
UPDATE: while this answers the original question, it's not very good C practise. 更新:虽然这回答了原始问题,但这并不是很好的C练习。 If, as the poster says, he wants to read a list of integers from a file and get it back as an array of long, then the prototype is probably going to look something like this:
如果正如海报所说,他想要从文件中读取整数列表并将其作为长数组返回,那么原型可能看起来像这样:
int readSeqFile(const char *const filename,long **longArray,size_t *const len);
and the implementation (in sketch form): 和实施(草图形式):
#include <stdio.h>
#include <stdlib.h>
const size_t longArrayChunkSize=100;
int readSeqFile(const char *const filename,long **longArray, size_t *const len)
{
FILE *fp;
size_t nInts=0,curBufferLen;
long tmp;
fp=fopen(filename,"r");
if(fp==NULL)
return -1;
*longArray=malloc(longArrayChunkSize*sizeof(long));
if(*longArray==NULL)
return -1;
curBufferLen=longArrayChunkSize;
// let's assume file is a list of integers, one per line
while(read from file and !feof())
{
(scan line into tmp)
longArray[nInts++]=tmp;
if(nInts==curBufferLen)
(realloc *longArray by longArrayChunkSize, increase curBufferLen)
}
*len=nInts;
fclose(fp);
return 0;
}
Call it like this: result=readSeqFile(filename,&longArray,&arrayLen);
这样调用:
result=readSeqFile(filename,&longArray,&arrayLen);
longArray
is of type long*
and it is the caller's responsibility to free it afterwards. longArray
的类型为long*
,然后调用者有责任将其释放。 The result is zero on success and -1 on error. 成功时结果为零,错误时结果为-1。
This is where you win with C++ and STL classes like vector<long>
since you can just push_back()
each long as it comes out of the file without having to worry about memeory management. 这是你使用C ++和STL类(例如
vector<long>
获胜的地方,因为只要push_back()
从文件出来就可以,而不必担心内存管理。
Typically for C you would pass a pointer and length 通常对于C,您将传递指针和长度
// returns number of elements written
size_t myMethodName(long* dest, size_t len)
{
//etc
}
Nevermind.. I got it: 没关系..我明白了:
long *readSeqFile(char *fileName)
Thanks anyway 不管怎么说,还是要谢谢你
In C, functions cannot return array types; 在C中,函数不能返回数组类型; they can return pointers to arrays, such as
他们可以返回指向数组的指针 ,例如
long (*readSeqFile(char *filename))[N]
{
...
}
the downside being that N must be a compile time constant if you're using a C89 or earlier compiler, or a C2011 compiler that doesn't support variable length arrays. 缺点是,如果您使用的是C89或更早版本的编译器,或者不支持可变长度数组的C2011编译器,则N必须是编译时常量。 You probably don't want to go this route if you don't know how big the array is supposed to be ahead of time.
如果你不知道阵列应该提前多大,你可能不想走这条路。
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