在python中使用def有多个参数

Question

So in java you can do something like this if you don't know how many parameters you are going to get

private void testMethod(String... testStringArray){

}

How can I do something like this in python

as I can't do something like this right?

def testMethod(...listA):

Answer 1

Are you talking about variable length argument lists? If so, take a look at *args , **kwargs .

See this Basic Guide and How to use *args and **kwargs in Python

Two short examples from [1] :

Using *args :

def test_var_args(farg, *args):
    print "formal arg:", farg
    for arg in args:
        print "another arg:", arg

test_var_args(1, "two", 3)

Results:

formal arg: 1
another arg: two
another arg: 3

and using **kwargs (keyword arguments):

def test_var_kwargs(farg, **kwargs):
    print "formal arg:", farg
    for key in kwargs:
        print "another keyword arg: %s: %s" % (key, kwargs[key])

test_var_kwargs(farg=1, myarg2="two", myarg3=3)

Results:

formal arg: 1
another keyword arg: myarg2: two
another keyword arg: myarg3: 3

Quoting from this SO question What do *args and **kwargs mean? :

Putting *args and/or **kwargs as the last items in your function definition's argument list allows that function to accept an arbitrary number of anonymous and/or keyword arguments.

Answer 2

Sounds like you want:

def func(*args):
      # args is a list of all arguments

This like a lot of other such information is covered in the Python tutorial , which you should read.