如何使gridView命令字段按钮进入ajax更新面板PostBackTrigger

Question

I have a gridview in an ajax update panel. I have set the different button events as AsyncPostBackTriggers but I want the select button to open a child web page so it has to be a postback. I tried the following:

<Triggers>
      <asp:AsyncPostBackTrigger ControlID="gvClients" EventName="RowCancelingEdit" />
      <asp:AsyncPostBackTrigger ControlID="gvClients" EventName="RowEditing" />
      <asp:AsyncPostBackTrigger ControlID="gvClients" EventName="RowUpdated" />
      <asp:AsyncPostBackTrigger ControlID="gvClients" EventName="RowUpdating" />
      <asp:AsyncPostBackTrigger ControlID="gvClients" EventName="Sorted" />
      <asp:AsyncPostBackTrigger ControlID="gvClients" EventName="Sorting" />
      <asp:PostBackTrigger ControlID="gvClients" />
</Triggers>

I recieved the following error:" System.ArgumentException: Control with ID 'gvClients' cannot be registered through both RegisterAsyncPostBackControl and RegisterPostBackControl. This can happen if you have conflicting triggers associated with the target control."

I tried accessing the select button from code behind and setting it as a trigger.

This is the code:

   protected void gvClients_RowDataBound(object sender, GridViewRowEventArgs e)
    {
       if (e.Row.RowType == DataControlRowType.DataRow)
        {     
            Button btnDtls = (Button)e.Row.Cells[0].Controls[2];
            string btnDtlsId = btnDtls.ID;
            PostBackTrigger trigger = new PostBackTrigger();
            trigger.ControlID = btnDtlsId;
            UpdatePanel1.Triggers.Add(trigger);
        }
    }

In debugging I saw that the ID for the button is "ctl01" but I'm getting this error: "A control with ID 'ctl01' could not be found for the trigger in UpdatePanel 'UpdatePanel1'". Is there a way of accessing a control field select button and setting it as a PostBackTrigger?

Answer 1

Since the button is inside a template, its final id is different and you can get it from the UniqueID property. http://msdn.microsoft.com/en-us/library/system.web.ui.control.uniqueid.aspx