[英]How do I replace more than 1 character in blackberry
I know how to replace a certain character with another character in a string: 我知道如何用字符串中的另一个字符替换某个字符:
System.out.println(replaceAll("Where are you??", "?", "")) System.out.println(replaceAll(“你在哪里??”,“?”,“”))
public static String replaceAll(String front, String pattern, String back){
if (front == null)
return "";
StringBuffer sb = new StringBuffer(); //A StringBuffer is created
int idx = -1;
int patIdx = 0;
while ((idx = front.indexOf(pattern, patIdx)) != -1)
{
sb.append(front.substring(patIdx, idx));
sb.append(back);
patIdx = idx + pattern.length();
}
sb.append(front.substring(patIdx));
return sb.toString();
}
This code will replace all ?
这段代码会取代所有?
with an empty space and would print out ("Where are you") 空的空间,将打印出来(“你在哪里”)
Now what I want to know is how can I replace more than 1 character. 现在我想知道的是如何替换超过1个字符。 In Java I can just use simple regex, but if in blackberry I write something like: 在Java中我可以使用简单的正则表达式,但如果在黑莓中我写了类似的东西:
System.out.println(replaceAll("Henry!! Where are you??", "!?", ""))
then blackberry doesn't pick it up. 然后黑莓不接。 So how do I overcome this limitation that blackberry has? 那么我该如何克服黑莓的这种局限呢?
There is not any method to do it what you want. 没有任何方法可以做到你想要的。 But i can suggest you that make an array of string of the pattern which you want to replace
. 但我可以建议你制作一个array of string of the pattern which you want to replace
。 Loop through the array of string get the string by their position and pass that in your 循环遍历字符串数组获取字符串的位置并将其传递给您的字符串
public static String replaceAll(String front, String pattern, String back)
. public static String replaceAll(String front, String pattern, String back)
。 Hope this will help you . 希望这会帮助你 。
If you want to replace any character in String front
that is used in String pattern
you can use toCharArray()
, iterate over all characters in pattern, check which is first to replace (which is nearest) and replace it. 如果要替换String pattern
中使用的String front
任何字符,可以使用toCharArray()
,遍历模式中的所有字符,检查哪个是第一个要替换的(最近的)并替换它。 What I mean is something like this 我的意思是这样的
public static String replaceAll(String front, String pattern, String back) {
if (front == null)
return "";
StringBuffer sb = new StringBuffer(); // A StringBuffer is created
int idx = -1;
int patIdx = 0;
boolean end = true;
int tmp = -1;
do {
end = true;
for (char c : pattern.toCharArray()) {
//System.out.println("searching for->"+c+" from patIdx="+patIdx+" idx="+idx);
if ((tmp = front.indexOf(c, patIdx)) != -1) {
//System.out.println("FOUND->"+c+" from patIdx="+patIdx+" idx="+idx+" tmp="+tmp);
if (idx == -1 || idx == patIdx-1 || (idx > patIdx && tmp < idx)){
end = false;
idx = tmp;
//System.out.println("setting replacement to ->"+c+" patIdx="+patIdx+" idx="+idx);
}
}
}
if (!end && idx != -1) {
//System.out.println("replacing patIdx="+patIdx+" idx="+idx);
sb.append(front.substring(patIdx, idx));
sb.append(back);
patIdx = idx+1;
}
//System.out.println("----");
}while(!end);
sb.append(front.substring(patIdx));
return sb.toString();
}
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