使用 Express 在动态路由上提供静态文件

Question

I want to serve static files as is commonly done with express.static(static_path) but on a dynamic route as is commonly done with

app.get('/my/dynamic/:route', function(req, res){
    // serve stuff here
});

A solution is hinted at in this comment by one of the developers but it isn't immediately clear to me what he means.

Answer 1

Okay. I found an example in the source code for Express' response object . This is a slightly modified version of that example.

app.get('/user/:uid/files/*', function(req, res){
    var uid = req.params.uid,
        path = req.params[0] ? req.params[0] : 'index.html';
    res.sendFile(path, {root: './public'});
});

It uses the res.sendFile method.

NOTE : security changes to sendFile require the use of the root option.

Answer 2

I use below code to serve the same static files requested by different urls:

server.use(express.static(__dirname + '/client/www'));
server.use('/en', express.static(__dirname + '/client/www'));
server.use('/zh', express.static(__dirname + '/client/www'));

Although this is not your case, it may help others who got here.

Answer 3

You can use res.sendfile or you could still utilize express.static :

const path = require('path');
const express = require('express');
const app = express();

// Dynamic path, but only match asset at specific segment.
app.use('/website/:foo/:bar/:asset', (req, res, next) => {
  req.url = req.params.asset; // <-- programmatically update url yourself
  express.static(__dirname + '/static')(req, res, next);
});         

// Or just the asset.
app.use('/website/*', (req, res, next) => {
  req.url = path.basename(req.originalUrl);
  express.static(__dirname + '/static')(req, res, next);
});

Answer 4

This should work:

app.use('/my/dynamic/:route', express.static('/static'));
app.get('/my/dynamic/:route', function(req, res){
    // serve stuff here
});

Documentation states that dynamic routes with app.use() works. See https://expressjs.com/en/guide/routing.html