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Integer.parseInt()问题

[英]Integer.parseInt() problems

My code is not giving me the right output. 我的代码没有给我正确的输出。 It reads numbers from a text file, converts them to an integer value and performs some multiplication on them. 它从文本文件中读取数字,将它们转换为整数值并对它们执行一些乘法运算。 But the the products that method findProduct() gives me are wrong, so I think I am using the Integer.parseInt() method incorrectly. 但是findProduct()方法给我的产品是错误的,所以我认为我错误地使用了Integer.parseInt()方法。

I guess what is throwing me off is that It is trying to tell me the product of 96086x67017=2144428166, When checking on my calculator it is around 643939395462. 我猜是什么让我失望的是它试图告诉我96086x67017 = 2144428166的产品,当我的计算器检查时它大约是643939395462。

/*
 * 
 * Find the greatest product of five consecutive digits in the 1000-digit number.

73167176531330624919225119674426574742355349194934
96983520312774506326239578318016984801869478851843
85861560789112949495459501737958331952853208805511
12540698747158523863050715693290963295227443043557
66896648950445244523161731856403098711121722383113
62229893423380308135336276614282806444486645238749
30358907296290491560440772390713810515859307960866
70172427121883998797908792274921901699720888093776
65727333001053367881220235421809751254540594752243
52584907711670556013604839586446706324415722155397
53697817977846174064955149290862569321978468622482
83972241375657056057490261407972968652414535100474
82166370484403199890008895243450658541227588666881
16427171479924442928230863465674813919123162824586
17866458359124566529476545682848912883142607690042
24219022671055626321111109370544217506941658960408
07198403850962455444362981230987879927244284909188
84580156166097919133875499200524063689912560717606
05886116467109405077541002256983155200055935729725
71636269561882670428252483600823257530420752963450

this text file is in Project_8.txt
*/


import java.io.*;
// Import the scanner class that is used for reading the text file
import java.util.*;


public class Project_8 {

// Data members================================
// Object used to read the text file
private Scanner scanner;



// Public Methods==============================
// Points the scaaner object in the direction of the text file. Outputs an error if file is not found
public void openFile(){

    try{
        // Note the whole file's path is required
        scanner = new Scanner(new File("/Users/nicolematthews/Desktop/Tim/Java WORKSPACE/Project_Euler/src/Project_8.txt"));

    }catch(Exception e){

        System.out.println("Could not find the File. Check file's address");

    }
}



public String readFile(){

    // Instantiating the scanner for user input ruins its application for reading files
    //scanner = new Scanner(System.in);

    // Method looks the text file and adds each line of the text to the String sequence.
    // the Method returns sequence

        String sequence = "";

        // While the scanner has more data to read
        while(scanner.hasNext()){

            sequence = sequence + scanner.next();

        }

    return sequence;
}





// This method simply closes the scanner object
public void closeFile(){

    scanner.close();
}









public int findProduct(String sequence){


    int highestProduct = 0;

    for(int i = 0; i < ( sequence.length() - 10 ); i++){

        // Extract adjacent 5 digit strings which will be converted to integers
        String num1 = sequence.substring(i, i + 5);

        String num2 = sequence.substring(i + 5, i + 10);

        if( Integer.parseInt(num1)*Integer.parseInt(num2) > highestProduct ){

            highestProduct = Integer.parseInt(num1)*Integer.parseInt(num2);

            System.out.println(num1);
            System.out.println(num2);
            System.out.println(highestProduct);
            System.out.println("\n");

        }

    }

    return highestProduct;

}



// Main Method =========================================
public static void main(String args[] ) throws IOException{



    Project_8 object = new Project_8();

    object.openFile();

    String Sequence = object.readFile();

    System.out.println(Sequence);


    System.out.printf("%d Is the highest product of five consecutive \n" +
            "digits in the 1000-digit number.", object.findProduct(Sequence));



    // Finally, close the file when we are done with it.
            object.closeFile();
    /* Find the greatest product of five consecutive digits in the 1000-digit number


    System.out.println(Sequence);

*/      





}
}

Your sequence index i is only advancing by 1 for each iteration, i++ , but you consume 10 characters on each iteration. 对于每次迭代, i++ ,你的序列索引i只前进1,但每次迭代你消耗10个字符。 You've indicated that this is your intent. 你已经表明这是你的意图。

You'll overflow a java int with many of the 5-digit sub-sequences from your data. 您将使用数据中的许多 5位子序列溢出java int For instance, your second product will be 31671 * 76531 = 2423813301 . 例如,您的第二个产品将是31671 * 76531 = 2423813301 This is larget than Integer.MAX_INT : 2^31 - 1 . 这比Integer.MAX_INT2 ^ 31 - 1大

Changing the findProduct method to use long and Long.parseLong() will fix this. findProduct方法更改为使用longLong.parseLong()将解决此问题。

I think the problem is caused by the number extractor part of the code, are all the numbers exactly 5 characters long? 我认为问题是由代码的数字提取器部分引起的,所有数字都是5个字符长吗? If that is not the case, your code won't work well because your code expects it to be 5 characters long. 如果不是这样,那么您的代码将无法正常运行,因为您的代码需要长度为5个字符。 If there are spaces inside, Integer.parseInt() will complain unless you call trim on it, which you have not done. 如果里面有空格, Integer.parseInt()会抱怨,除非你调用它上面的trim ,你没有做过。

Your if statement does too much all at once: 你的if语句一次性做得太多了:

if( Integer.parseInt(num1)*Integer.parseInt(num2) > highestProduct ){ 

You should break this up to assign each int value to a separate variable. 您应该将其分解为将每个int值分配给单独的变量。 That way you can print these values to see if they are the correct one. 这样,您可以打印这些值以查看它们是否正确。 Also, it will allow you to remove the rpeated calls to Integer.parseInt() in the next line. 此外,它将允许您删除下一行中对Integer.parseInt()的rpeated调用。

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