使用xslt 2.0将字符串模式转换为XML

Question

MSH.1:MSH.2:MSH.3:PID.1:PID.2:ORC.1:ORC.3

above string pattern I would like to transform into below XML format

<filters>
<element group="MSH">
  <location path="MSH.1"/>
  <location path="MSH.2"/>
  <location path="MSH.3"/>
</element>
<element group="PID">
  <location path="PID.1"/>
  <location path="PID.2"/>
</element>
<element group="ORC">
  <location path="ORC.1"/>
  <location path-"ORC.3"/>
</elment>
</filters>

Can I have sample XSLT to achieve above scenario

Note : I am making use of XSLT 2.0 ans saxon transformer

Answer 1

Assuming you start the transformation in Saxon with parameters

-it:main in=MSH.1:MSH.2:MSH.3:PID.1:PID.2:ORC.1:ORC.3

try

<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:param name="in"/>

<xsl:template name="main">
<filters>
  <xsl:variable name="tokens" select="tokenize($in, ':')"/>
  <xsl:for-each-group select="$tokens" group-by="substring-before(., '.')"/>
   <element group="{current-grouping-key()}">
     <xsl:for-each select="current-group()">
       <location path="{.}"/>
     </xsl:for-each>
   </element>
  </xsl:for-each-group>
</filters>
<xsl:template>

</xsl:stylesheet>

Answer 2

You can use the unparsed-text() function in XSLT 2.0 to load a document as a string variable.

You would then probably use the xsl:analyze-string instruction to split the string, first on the ":" character, then possibly on the period character.

Answer 3

XSLT is meant to manipulate XML (into something else). So you will have to XMLize your string first, at minimum

<xmlize>MSH.1:MSH.2:MSH.3:PID.1:PID.2:ORC.1:ORC.3</xmlize>

You can then have an XSLT matching on the root element and you can use `tokenize()' to process your string. See this discussion

Doing this with XSLT is a bit weird; can't you use another script/language that has String manipulation functions with regular expressions splitting ?

nb: when you "xmlize", do not forget to escape '<' '>' and '&' if appropriate