将shared_ptr <T>转换为shared_ptr <void>

Question

I have a structure:

struct Params {
   std::shared_ptr<void> user_data;
   /* ... */
};

I want to use it like this:

int main() {
  std::shared_ptr<SpecializedParams> sp(new SpecializedParams(100));
  Params params;
  /* ... */
  params.user_data = std::static_pointer_cast<void>(sp); 
  /* ... */
  std::shared_ptr<SpecializedParams> sp2 = 
    std::static_pointer_cast<SpecializedParams>(
      params.user_data
    );
  /* ... */
  return 0;
}

Is this valid and safe?

Answer 1

The code, that actual deletes the shared object is determined when the shared pointer is created (that's why you need a complete type, when constructing the shared_ptr and not, when destructing the shared_ptr). Thus even when your shared_ptr is the last pointer that points to your SpecializedParams object, the object will get correctly destroyed.

Answer 2

This should be safe as the void casted item is a shared_ptr too. It will add a reference to the existing element and it will not be released until the void casted item goes away.