Ms-Access GROUP BY，TOP查询

Question

I am using the following query on a .mdb file with the following results.

SELECT tableA.id, tableA.type, tableA.date, SUM(tableA.val) AS total, tableB.SumB
FROM tableA LEFT JOIN tableB ON tableB.id = tableA.id
GROUP BY tableA.id, tableA.type, tableA.date, tableB.SumB ;

results:

I need only the first record from the group of records with the same type and date .

I would use DISTINCT but the problem is that I have a different field (in this example id ).

Any suggestions?

Thanks

PS Case 2:

Ids are the same for the red records but we have an additional column 'name' with different string values.

Answer 1

Use min of id and remove it from Group by clause

SELECT min(tableA.id) as id, tableA.type, tableA.date, 
SUM(tableA.val) AS total, tableB.SumB 
FROM tableA LEFT JOIN tableB ON tableB.id = tableA.id 
GROUP BY tableA.type, tableA.date, tableB.SumB ;