OSX - ZSH - PATH - /usr/bin 重复

Question

I need some help to understand why my path looks like the way it looks.

Issuing echo $PATH in zsh returns:

/Library/Frameworks/Python.framework/Versions/3.2/bin:/usr/bin/:/bin:/usr/sbin:/sbin:
/usr/local/bin:/usr/X11/bin:/usr/local/go/bin:/usr/bin

Now, let's have a closer look of the different parts:

- /Library/Frameworks/Python.framework/Versions/3.2/bin:

it comes from my.zprofile (Python 3 installation)

- /usr/bin/: 
- /bin: 
- /usr/sbin:
- /sbin:
- /usr/local/bin:

These parts come from my /etc/paths folder.

- /usr/X11/bin:

This part come from my etc/path.d folder

- /usr/local/go/bin:

This part was added during GO installation.

- /usr/bin

???

I have looked at -/etc/paths -.zshrc -.zprofile -.profile -/etc/profile -.zshenv. None of them sourced or added a second /user/bin neither to the PATH.

How can I remove the second /user/bin from my PATH if I don't know which file to edit?

Thank you.

Answer 1

在ZSH中，删除PATH变量中的重复项是通过typeset -U PATH完成的，而不是typeset -u PATH （后者只是将内容转换为大写...）

Answer 2

While this doesn't explain where the second /usr/bin comes from, you can put typeset -u PATH after the last place you append anything to $PATH. This will remove duplicate entries.

Answer 3

Use zsh to enter the command zsh shell and then use typeset -u PATH to remove the duplicates. I have used small -u in typeset, but it has turned the variables into uppercase and hasnt removed the duplicates.