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LINQ TO XML,如何用新值替换值c#

[英]LINQ TO XML, How to replace values with new values c#

Below is my Sample XML File:- 以下是我的示例XML文件:

I just want to replace date values with current date using LINQ to XML in C#. 我只想在C#中使用LINQ to XML将日期值替换为当前日期。

<?xml version="1.0" encoding="UTF-8"?>
<BasicImport xmlns="http://www.uk.SSp.com/SSR/XTI/Traffic/0010" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.uk.nds.com/SSR/XTI/Traffic/0010 0010.xsd" utcOffset="+05:30" frameRate="25">
  <SiEventSchedule deleteStart="2012/01/21 00:00:00" deleteEnd="2012/01/21 23:59:59">
    <siService>Ssp</siService>
    <playoutSource>Ssp</playoutSource>
    <activationSourceId>0</activationSourceId>
    <CaSchedule deleteStart="2012/01/21 00:00:00" deleteEnd="2012/01/21 23:59:59" />
    <SiEvent>
      <displayDateTime>2012/01/21 00:00:00</displayDateTime>
      <activationDateTime>2012/01/21 00:00:00</activationDateTime>
      <displayDuration>00:30:00</displayDuration>
      <siTrafficKey>056049263</siTrafficKey>
      <detailKey>056049263 2012-07-12</detailKey>
     </SiEvent>
   </SiEventSchedule>
</BasicImport>

Which date values? 哪个日期值? All of them? 都是 Specific elements? 具体要素? For example, this will replace all displayDateTime elements with the current date - in standard XML format, which isn't what your source XML contains... if you want a different format, you should use DateTime.ToString and replace the contents of the elements with the relevant text. 例如,这会将所有displayDateTime元素替换为当前日期-标准XML格式,而不是您的源XML包含的格式...如果您希望使用其他格式,则应使用DateTime.ToString并替换其中的内容元素以及相关文字。

using System;
using System.Linq;
using System.Xml.Linq;

class Test
{
    static void Main()
    {
        XNamespace ns = "http://www.uk.ssp.com/SSR/XTI/Traffic/0010";
        XDocument doc = XDocument.Load("ssp.xml");

        var elements = doc.Descendants(ns + "displayDateTime")
                          .ToList();

        var today = DateTime.Today;
        foreach (var element in elements)
        {
            element.ReplaceAll(today);
        }
        Console.WriteLine(doc);
    }
}

You could do on following manner 您可以按照以下方式进行

    [Test]
    public void Test()
    {
        XElement root = XElement.Load("Data.xml");
        root.Descendants()
           .Where(x => x.Name.LocalName == "displayDateTime")
           .ToList()
           .ForEach(x => x.ReplaceNodes(GetDate(x)));
    }

    private static DateTime GetDate(XElement element)
    {
         return DateTime.Today.Add(DateTime.Parse(element.Value).TimeOfDay);
    }

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