在javascript中从当前日期找出上一年的日期

Question

I need to find out the previous year date from current date and then set as minDate in jQuery UIdatepicker in javascript

My date formaqt is dd-mm-yy

Ie

• current date is 25-07-2012
• I need to get 25-07-2011

Answer 1

You need to use getFullYear()

and then generate new Date

var d = new Date(2012, 7, 25);
d.setFullYear(d.getFullYear() - 1);

Answer 2

Try this

var d = new Date();
var pastYear = d.getFullYear() - 1;
d.setFullYear(pastYear);
console.log(d);

Answer 3

this solution will help.

new Date(new Date().setFullYear(new Date().getFullYear() - 1));

Answer 4

Use this:

 var date = new Date();
 var intYear = date.getFullYear() - 1;

Answer 5

Datepicker allows you to put a number as the minDate option, and it uses that as an offset from the current date. So you can write:

minDate: -365

to specify 1 year ago. This doesn't take leap years into account, though.

Answer 6

I need to find out the previous year date from current date and then set as minDate in jQuery UIdatepicker in javascript

My date formaqt is dd-mm-yy

Ie

• current date is 25-07-2012
• I need to get 25-07-2011

Answer 7

For strings:

curdate.substr(0, 6)+(curdate.substr(6)-1);

If you'd use a Date object , you could easily subtract a year with the set[Full]Year method.

Answer 8

you can define a new date or an existing date as d variable

var d = new Date();

then you can put date, month and year to the new date string using ${variableName} , Also you must add 1 to d.getMonth() and substract 1 from d.getFullYear()

var previousYearDate = `${d.getDate()}-${d.getMonth() + 1}-${d.getFullYear() - 1}`;

Answer 9

var today = new Date();
var curyear = today.getFullYear();
var curyearMonth = today.getMonth() + 1;
var curyearDay = today.getDate();
var lastYear = curyear - 1;
if ((curyearMonth == 2) && (curyearDay == 29)) {
    curyearDay = 28;
}

var lastYearDisplay = ("0000" + lastYear.toString()).slice(-4) + "-" + ("00" + curyearMonth.toString()).slice(-2) + "-" + ("00" + curyearDay.toString()).slice(-2);
alert("LastWeekDate : " + lastYearDisplay);

Answer 10

I found this very useful:

new Date(new Date().setFullYear(new Date().getFullYear() - 1)).toISOString().slice(0, 10);

Answer 11

To avoid the Date object (if that is what OP wishes):

var currDate = '25-07-2012';
var dateParts = currDate.split('-');
dateParts[2] = parseInt(dateParts[2], 10) - 1;
alert(dateParts.join('-'));​

Answer 12

var date = CALC.today(); //(function in my dev-enviro - gives today's date)
var year = formatDate(date, 'yyyy'); //year is 2016
year = parseInt(year);               //make sure '2016' becomes an integer
year = year -1;                      // var year is now: 2015.

//its been a while, but that's what I did from memory.

Answer 13

  function getTodayDate() {
        var today = new Date();
        var dd = today.getDate();
        var mm = today.getMonth() + 1; //January is not 0!
        var yyyy = today.getFullYear();
        if (dd < 10) { dd = '0' + dd }
        if (mm < 10) { mm = '0' + mm }
        today = yyyy + '-' + mm + '-' + dd;
        return today;
    };
    function getYearAgo(){
    var lastYear = new Date();
    var dd = lastYear.getDate();
    var mm = lastYear.getMonth() + 1; //January is not 0!
    var yyyy = lastYear.getFullYear(getTodayDate) - 1;
    if (dd < 10) { dd = '0' + dd }
    if (mm < 10) { mm = '0' + mm }
    lastYear = yyyy + '-' + mm + '-' + dd;     
    return lastYear;
    }