使用元组和operator.itemgetter对字典进行排序

Question

I am before my last milestone preparing suitable output. Its quite simple, I think, but my approach doesn't work:

Given an dictionary like

mydict = {x1: (val1, dist1, (lat1, lon1)), x2: (val2, dist2, (lat2, lon2)), ...}

I tried to sort this in a nested way in an array, first using the "values" and if equals, sorting for "dist".

However, I did my homework and tried it using this way:

import operator
s = sorted(mydict.iteritems(), key=operator.itemgetter(1))

The thing is that if the sort method would be appliable to tuples, it would be quite easy, because it's already in the right order.

Unfortunately I get:

'list' object is not callable

Do you have an idea?

Answer 1

您是否可能重写了用列表值sorted的名称？

Answer 2

The thing is that if the sort method would be appliable to tuples, it would be quite easy

sorted() works perfectly fine on a list of tuples, in which case it uses a lexicographic ordering .

(a,b) ≤ (a′,b′) if and only if a < a′ or (a = a′ and b ≤ b′).

This can be expanded to any number of dimensions.

>>> sorted([(10, 1), (5, 3), (6, 5), (3, 2), (5, 10)])
[(3, 2), (5, 3), (5, 10), (6, 5), (10, 1)]