jQuery绑定没有DOM元素的AJAX事件

Question

In the documentation of jQuery AJAX Events all the examples use a jQuery DOM Element for declare a binding like this:

$('.log').ajaxSend( hander );

I want to catch jQuery AJAX Events without the need of having a DOM Element to attach them, like this:

$.ajaxSend( function( event, jqXHR, ajaxOptions ){
  console.log( "ajaxSend" );
  console.log( "ajaxSend.event", event );
  console.log( "ajaxSend.jqXHR", jqXHR );
  console.log( "ajaxSend.ajaxOptions", ajaxOptions );
});

But It looks like it doesn't work:

Uncaught TypeError: Object function (a,b){return new e.fn.init(a,b,h)} has no method 'ajaxSend' 

Any suggestion?

Answer 1

你可以使用这个document ：

$(document).ajaxSend( hander );

Answer 2

听起来你想要自定义你的ajax调用，其中使用$ .fn.ajax调用很有效：

$.ajax('{your_url}', options);