计算Python中一个文本文件包含多少句点

Question

I would like to write a code that will read and open a text file and tell me how many "." (full stops) it contains

I have something like this but i don't know what to do now?!

f = open( "mustang.txt", "r" )
    a = []
    for line in f:

Answer 1

with open('mustang.txt') as f:
    s = sum(line.count(".") for line in f)

Answer 2

I'd do it like so:

with open('mustang.txt', 'r') as handle:
  count = handle.read().count('.')

If your file isn't too big, just load it into memory as a string and count the dots.

Answer 3

with open('mustang.txt') as f:
    fullstops = 0
    for line in f:
        fullstops += line.count('.')

Answer 4

This will work:

with open('mustangused.txt') as inf:
    count = 0
    for line in inf:
        count += line.count('.')

print 'found %d periods in file.' % count

Answer 5

Assuming there is absolutely no danger of your file being so large it will cause your computer to run out of memory (for instance, in a production environment where users can select arbitrary files, you may not wish to use this method):

f = open("mustang.txt", "r")
count = f.read().count('.')
f.close()
print count

More properly:

with open("mustang.txt", "r") as f:
    count = f.read().count('.')
print count

Answer 6

even with Regular Expression

import re
with open('filename.txt','r') as f:
    c = re.findall('\.+',f.read())
    if c:print len(c)