为什么这个字符串不能正确逃逸？

Question

我有一个如下所示的字符串，尽管它在到达冒号时会引发错误，但我使用@来转义所有内容：

string vmListCommand = @"vim-cmd vmsvc/getallvms | sed '1d' | awk '{if ($1 > 0) print $1":"$2}'";

Answer 1

Remove @ and escape double quotes using \\ :

string vmListCommand = "vim-cmd vmsvc/getallvms | sed '1d' | awk '{if ($1 > 0) print $1\":\"$2}'";

You wrote:

I have used @ to escape everything

@ is used to change escaping bahaviour, not to escape everything . If a string is prefixed with @ then escape sequences ( \\ ) are ignored.

Answer 2

Use \\ for escape in your string.

Example:

string str1 ="hello\\";

Answer 3

您需要删除文字并转义

string vmListCommand = "vim-cmd vmsvc/getallvms | sed '1d' | awk '{if ($1 > 0) print $1\":\"$2}'";

Answer 4

There is one character that needs to be escaped in literal strings. The double quote " . If you don't escape it, how would the compiler know which " are part of the string, and which terminate the string?

To escape a " in a literal string, simply double it:

 @"vim-cmd vmsvc/getallvms | sed '1d' | awk '{if ($1 > 0) print $1"":""$2}'"

Alternatively you could switch to the normal string syntax, and escape with \\ .