[英]Getting the value of option chosen by the user
In my index file where the form and function are located, named: 在我的表单和函数所在的索引文件中,名为:
index.php index.php
$(function() {
$.ajax({
type: "POST",
url: "invtype.php",
data: "getrevenuetype=true",
success: function(b){
$("#revenueType").html(b)
}
})
})
<span name="revenueType" id="revenueType"></span><br/>
invtype.php invtype.php
<?php
mysql_connect("","","") or die('Error: '.mysql_error());
mysql_select_db("dbname");
if(isset($_POST['getrevenuetype'])) {
$sql3 = mysql_query("SELECT * FROM chartofaccount WHERE accountnumber >= 4000 and accountnumber <= 4999");
$acct = '';
$acctrow = mysql_num_rows($sql3);
if($acctrow > 0) {
echo 'Revenue Type:<select name="rename">';
while($chartrow = mysql_fetch_array($sql3)) {
$revenueaccountname = $chartrow['accountname'];
$acct .= '<option value="$revenueaccountname"> '. $revenueaccountname .' </option>';
}
}
}
echo $acct;
echo '</select>';
My question is how will I get or what code should I put on to get the value of the option selected by the user? 我的问题是,如何获取或应该使用什么代码来获取用户选择的选项的值? My purpose in getting the value is that I want to put it in another php where it will be used as var in inserting data into MySQL.
我获取值的目的是,我想将其放在另一个php中,在将数据插入MySQL时将用作var。 already tried this code:
$name = $_POST['rename'];
已经尝试过以下代码:
$name = $_POST['rename'];
then included 'invtype.php'; 然后包含'invtype.php'; on the other php file (this is where I will use the value of option selected) but it doesn't seem to work.
在另一个php文件上(这是我将使用所选选项的值的位置),但它似乎不起作用。 I know my code is all messed up and I'm really sorry about it, but guys if you can help I would really appreciate it.
我知道我的代码都搞砸了,对此我感到非常抱歉,但是如果您能帮助我,我将非常感谢。
you need to add , for example, ' for first time response 您需要添加“例如,用于首次响应
echo $acct;
echo '</select>';
echo '<input type="submit id="submit" value="" />';
than add js 比添加js
$('#sumbit').click(function(){
var name = $('select[name=rename]').val();
$.ajax({
type: "POST",
url: "invtype.php",
data: "rename=1&name="+name,
success: function(b){
$("#revenueType").html(b)
}
})
});
than change invtype.php 比更改invtype.php
if(isset($_POST['rename'])) {
$name = $_POST['name'];
//work with base
}
How's this? 这个怎么样? Give your form an id attribute and replace the formid with it :)
给您的表单一个id属性,并将其替换为:)
$(function() {
$.ajax({
type: "POST",
url: "invtype.php",
data: "getrevenuetype=true&selectedoption=" + $('#formid option:selected').val(),
success: function(b){
$("#revenueType").html(b)
}
})
})
After the select
tag is added to the page and an option
is selected by the user, you can then send the selected value with a button click like this: 将
select
标记添加到页面并由用户选择一个option
,您可以通过单击按钮发送所选值,如下所示:
$("#btn").click(function(){
$.ajax({
type: "POST",
url: "server.php",
data: "value=" + $('option:selected').val(),
success: function(b){
alert('Sent successfully!');
}
})
})
$('select[name="rename"] option:select').val()
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