如何将ID与mysql中不同表的名称匹配？

Question

A. event_choices

event_id | res_id | 
4        | 10     | 

B. restaurants 

res_id     | res_name | 
10         | xyz      | 

C. event
event_id   | event_name | 
4          | birthday   | 

I've been trying inner join to try match the names to id but been unsuccessful

select event_id as id from event_choices inner join restaurants on res_id.id = res_name

any help would be greatly appreciated, very new to php/mysql

Answer 1

Try:

SELECT event_id, res_name FROM event_choices, restaurants WHERE event_choices.res_id = restaurants.res_id

Enjoy ^_^

Answer 2

SELECT event.event_name, restaurants.res_name FROM event_choices 
    INNER JOIN restaurants ON event_choices.res_id = restaurants.res_id
    INNER JOIN event ON event_choices.event_id = event.event_id 

could work.

If you select * instead of event.event_name you should get all data and be able to pick from it. You can also select specific fields in the form of <table>.<field> .

EDIT: added res_name

Answer 3

尝试这个：

  select ec.event_id as id from event_choices ec inner join restaurants r on ec.res_id = r.res_id