pymongo如何查询嵌套文档以忽略键但得到它的值？

Question

I have a documents inserted in mongoDB in the format as below:

{'Name':{'Surname':{'JON':{'AGE':10}}}}

In the example above I want to build a query to ignor the 'JON' but fetch AGE value of all users.

I tried like:

db.names.find({'Name.Surname':{$regex:'.'}}) but didn't work....

What I'm looking for is something like:

db.names.find({'Name.Surname.<matchanything>.AGE':{$gt:0}})

Answer 1

I think the document scheme you have is going to make it hard for you to query, even if MongoDB supported wildcard matches in this manner (it currently does not). Basically it would come down to doing a lot of table scans.

Is there a reason for having Age as a property of surname?

An alternative would be to have a document structure more along the lines of

{
    "_id" : ObjectId(),
    "Name" : "something",
    "Surname" : "JON",
    "Age" : 10
}

Which would be more handy for queries:

db.user.find({"Name":"something"})
db.user.find({"Age":{"$gte":5}})