如何在Erlang中创建一系列已注册的进程名称？

Question

At the moment I am using the following to create and register processes individually:

register(name, spawn(fun() -> myfun())).

I would like to create a list of N registered Pids with names as follows:

pid1
pid2
pid3
.
.
.
pidN

Can anyone recommend a way of doing this?

Answer 1

如果要为同一个函数生成多个进程，可以使用列表list_to_atom/1并使用字符串和list_to_atom/1串联：

[register(list_to_atom("pid" ++ integer_to_list(X)), spawn(fun() -> myFun() end)) || X <- lists:seq(1,10)].

Answer 2

You might use following:

if you want to execute same function in multiply processes and register each process under different names:

lists:foreach( 
   fun( Name ) -> 
      register( Name, spawn( fun() -> myfun() end ) ) 
   end, 
   [ pid1, pid2, pid3 ] ).

or if you want to execute different functions in different processes:

lists:foreach( 
   fun( { Name, Func } ) -> 
      register( Name, spawn( fun() -> Func() end ) ) 
   end, 
   [ { pid1, f1 }, { pid2, f2 }, { pid3, f3 } ] ).

( f1, f2, f3 - are functions )

and finally, if you want to execute same function in N processes, you might do next:

N = 20, %number of processes
lists:map( 
   fun( Num ) -> 
      register( 
         list_to_atom( "pid" ++ integer_to_list( Num ) ), 
         spawn( fun() -> myfun() end ) ) 
   end, 
   lists:seq( 1, N ) ).